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Pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid with density 2000 kg/m3 . The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points is
- a)98.1 N/m2
- b)981 N/m2
- c)1962 N/m2
- d)19620 N/m2
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Pressure drop of water flowing through a pipe between two points is m...
Considering the decrease in pressure along direction of flow the situation will be as shown in the figure.
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Equating Pressures at ① and ②
pA + ρwg (h + 10) / 100 = pB + ρwg (h) / 100 + ρmg ( 10 / 100)
pA − pB = (ρm − ρw)g ( 10 / 100)
pA − pB = (2000 − 1000) × 9.81 × 0.1
pA − pB = 981 Pa
Most Upvoted Answer
Pressure drop of water flowing through a pipe between two points is m...
Given:
- Density of manometric liquid (ρ) = 2000 kg/m3
- Difference in height of manometric liquid (h) = 10 cm = 0.1 m
To find:
Pressure drop between the two points.
Solution:
The pressure drop between two points can be determined using the formula:
ΔP = ρgh
Where:
ΔP = pressure drop
ρ = density of the liquid
g = acceleration due to gravity
h = height difference
Acceleration due to gravity:
The acceleration due to gravity (g) is approximately 9.81 m/s2.
Calculating pressure drop:
Substituting the given values into the formula:
ΔP = 2000 kg/m3 × 9.81 m/s2 × 0.1 m
Simplifying the expression:
ΔP = 1962 N/m2
Therefore, the pressure drop between the two points is 1962 N/m2, which corresponds to option B.
- Density of manometric liquid (ρ) = 2000 kg/m3
- Difference in height of manometric liquid (h) = 10 cm = 0.1 m
To find:
Pressure drop between the two points.
Solution:
The pressure drop between two points can be determined using the formula:
ΔP = ρgh
Where:
ΔP = pressure drop
ρ = density of the liquid
g = acceleration due to gravity
h = height difference
Acceleration due to gravity:
The acceleration due to gravity (g) is approximately 9.81 m/s2.
Calculating pressure drop:
Substituting the given values into the formula:
ΔP = 2000 kg/m3 × 9.81 m/s2 × 0.1 m
Simplifying the expression:
ΔP = 1962 N/m2
Therefore, the pressure drop between the two points is 1962 N/m2, which corresponds to option B.
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Pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid with density 2000 kg/m3 . The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points isa) 98.1 N/m2b) 981 N/m2c) 1962 N/m2d) 19620 N/m2Correct answer is option 'B'. Can you explain this answer?
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Pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid with density 2000 kg/m3 . The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points isa) 98.1 N/m2b) 981 N/m2c) 1962 N/m2d) 19620 N/m2Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid with density 2000 kg/m3 . The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points isa) 98.1 N/m2b) 981 N/m2c) 1962 N/m2d) 19620 N/m2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid with density 2000 kg/m3 . The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points isa) 98.1 N/m2b) 981 N/m2c) 1962 N/m2d) 19620 N/m2Correct answer is option 'B'. Can you explain this answer?.
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