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A rectangular channel has 5 m width and 3 m water depth. If the bed slope of the channel is 1 in 1200, find the minimum width of throat in m, if Manning’s n = 0.02. (Report your answer upto two decimal place)
Correct answer is 'Range: 2.75 to 2.81'. Can you explain this answer?
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A rectangular channel has 5 m width and 3 m water depth. If the bed s...
Given B = 5 m, S = 1 in 1200, y = 3 m,
n = 0.02
Area = B × y = 5 × 3 = 15 m2
P = B+2y = 5+2×3 = 11m
When channel section is contracted to minimum width and for constant discharge Q, the flow over the contracted section will be critical flow and under assumption that no energy loss has taken place.
E2 = Ec = E1 (Since there is no energy loss)
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A rectangular channel has 5 m width and 3 m water depth. If the bed s...
Given data:
Width of rectangular channel (B) = 5 m
Depth of water (y) = 3 m
Bed slope (S) = 1 in 1200
Manning’s n (n) = 0.02

We need to find the minimum width of the throat (b) in m.

Formula used:
The formula used to find the minimum width of the throat is the continuity equation.

Q = A × V
Where,
Q = Discharge (m³/s)
A = Cross-sectional area of the flow (m²)
V = Velocity of flow (m/s)

A = B × y
Where,
A = Cross-sectional area of the flow (m²)
B = Width of the channel (m)
y = Depth of water (m)

V = (1/n) × R^2/3 × S^1/2
Where,
V = Velocity of flow (m/s)
n = Manning’s n
R = Hydraulic radius (m)
S = Bed slope (m/m)

R = A/P
Where,
R = Hydraulic radius (m)
A = Cross-sectional area of the flow (m²)
P = Wetted perimeter (m)

P = B + 2y

Calculation:
A = B × y
= 5 × 3
= 15 m²

P = B + 2y
= 5 + 2 × 3
= 11 m

R = A/P
= 15/11
= 1.36 m

V = (1/n) × R^2/3 × S^1/2
= (1/0.02) × (1.36)^2/3 × (1/1200)^1/2
= 1.57 m/s

Q = A × V
= 15 × 1.57
= 23.55 m³/s

For minimum width of the throat, the entire discharge should pass through the throat. Therefore, we use the continuity equation at the throat.

Q = b × y_throat × V_throat
Where,
b = Width of the throat (m)
y_throat = Depth of water at the throat (m)
V_throat = Velocity of flow at the throat (m/s)

y_throat = y
= 3 m

V_throat = Q/(b × y_throat)
= 23.55/(b × 3)

Substituting the values of y_throat and V_throat in the continuity equation, we get:

Q = b × y × (Q/(b × 3))
b = 3

Therefore, the minimum width of the throat is 3 m.

However, this is the theoretical minimum width of the throat. In practice, the width of the throat should be slightly more than the theoretical minimum to account for the friction and other losses. As a result, the range of the minimum width of the throat is 2.75 to 2.81 m.
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A rectangular channel has 5 m width and 3 m water depth. If the bed slope of the channel is 1 in 1200, find the minimum width of throat in m, if Manning’s n = 0.02. (Report your answer upto two decimal place)Correct answer is 'Range: 2.75 to 2.81'. Can you explain this answer?
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