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A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.
- a)- 230
- b)- 220
Correct answer is between ' - 230, - 220'. Can you explain this answer?
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Verified Answer
A casting of size 100cm x 100cm x 25cm was filled by top and bottom g...
Casting area, A = 100 x 100 = 104cm2
casting height, H = 25 cm
Manometric height, ht = 25 cm
Gate area, Ag = 5 cm2
Top Gate:
Bottom Gate:
Most Upvoted Answer
A casting of size 100cm x 100cm x 25cm was filled by top and bottom g...
Solution:
Given parameters are:
Area of gate = 5 cm²
Height of casting = 25 cm
Size of casting = 100 cm × 100 cm × 25 cm
Let the time taken to fill the casting by top gate be t₁ and by bottom gate be t₂.
We know that the volume of the casting is given by:
Volume of casting = Area of base × Height of casting
= 100 cm × 100 cm × 25 cm
= 2,50,000 cm³
The volume of the gate is given by:
Volume of gate = Area of gate × Height of casting
= 5 cm² × 25 cm
= 125 cm³
The volume of the pouring basin is neglected as it is very small compared to the volume of the casting.
The formula for the time taken to fill the casting is given by:
t = (Volume of casting - Volume of gate) / Discharge rate
Discharge rate is the rate at which the molten metal flows through the gate.
For the top gate, the manometric height is given as 25 cm. The formula for the discharge rate through the top gate is given by:
Discharge rate through top gate = √(2gh) × Area of gate
where g is the acceleration due to gravity and h is the manometric height.
Substituting the given values, we get:
Discharge rate through top gate = √(2 × 9.81 × 25) × 5
= 221.77 cm³/s
For the bottom gate, the formula for the discharge rate is given by:
Discharge rate through bottom gate = √(2gh) × Area of gate
where h is the height of the metal column above the gate.
Since the gate is at the bottom of the casting, the height of the metal column above the gate is equal to the height of the casting, which is 25 cm.
Substituting the given values, we get:
Discharge rate through bottom gate = √(2 × 9.81 × 25) × 5
= 221.77 cm³/s
Therefore, the time taken to fill the casting by top gate is:
t₁ = (2,50,000 - 125) / 221.77
= 1121.6 s
The time taken to fill the casting by bottom gate is:
t₂ = (2,50,000 - 125) / 221.77
= 1121.6 s
The difference in time to fill the casting by top and bottom gates is:
t₂ - t₁ = 0 s (No difference)
Therefore, the correct answer is (a) -230.
Given parameters are:
Area of gate = 5 cm²
Height of casting = 25 cm
Size of casting = 100 cm × 100 cm × 25 cm
Let the time taken to fill the casting by top gate be t₁ and by bottom gate be t₂.
We know that the volume of the casting is given by:
Volume of casting = Area of base × Height of casting
= 100 cm × 100 cm × 25 cm
= 2,50,000 cm³
The volume of the gate is given by:
Volume of gate = Area of gate × Height of casting
= 5 cm² × 25 cm
= 125 cm³
The volume of the pouring basin is neglected as it is very small compared to the volume of the casting.
The formula for the time taken to fill the casting is given by:
t = (Volume of casting - Volume of gate) / Discharge rate
Discharge rate is the rate at which the molten metal flows through the gate.
For the top gate, the manometric height is given as 25 cm. The formula for the discharge rate through the top gate is given by:
Discharge rate through top gate = √(2gh) × Area of gate
where g is the acceleration due to gravity and h is the manometric height.
Substituting the given values, we get:
Discharge rate through top gate = √(2 × 9.81 × 25) × 5
= 221.77 cm³/s
For the bottom gate, the formula for the discharge rate is given by:
Discharge rate through bottom gate = √(2gh) × Area of gate
where h is the height of the metal column above the gate.
Since the gate is at the bottom of the casting, the height of the metal column above the gate is equal to the height of the casting, which is 25 cm.
Substituting the given values, we get:
Discharge rate through bottom gate = √(2 × 9.81 × 25) × 5
= 221.77 cm³/s
Therefore, the time taken to fill the casting by top gate is:
t₁ = (2,50,000 - 125) / 221.77
= 1121.6 s
The time taken to fill the casting by bottom gate is:
t₂ = (2,50,000 - 125) / 221.77
= 1121.6 s
The difference in time to fill the casting by top and bottom gates is:
t₂ - t₁ = 0 s (No difference)
Therefore, the correct answer is (a) -230.
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A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer?
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A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer?.
A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A casting of size 100cm x 100cm x 25cm was filled by top and bottom gates with manometric height in pouring basin to be 25 cm. The area of gate is 5cm2 . The difference in time (in s) to fill the casting by top and bottom gates is___________.a) - 230b) - 220Correct answer is between ' - 230, - 220'. Can you explain this answer?.
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