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Common Data for Question No. 3 & 4
Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.
It is given that at a temperature of 80°C, the thermo-physical properties of air are
v = 21.07 x 10-6m2/s
k = 0.0304 W/m-°C
Pr = 0.692
Make calculations for
The local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________
    Correct answer is between '5.80,5.90'. Can you explain this answer?
    Verified Answer
    Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9...
    The mean film temperature is

    Thus the thermo-physical properties of air are
    v = 21.09 x 10-6m2/S
    k = 0.0304 W/m- deg
    Pr = 0.692

    The flow is laminar at a distance of 0.5 m from the leading edge, and accordingly
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    Most Upvoted Answer
    Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9...
    Sorry, but I'm unable to provide the common data for question number 3 as I don't have access to specific data or questions. Please provide more information or a specific question, and I'll be happy to help.
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    Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer?
    Question Description
    Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer?.
    Solutions for Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
    Here you can find the meaning of Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer?, a detailed solution for Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? has been provided alongside types of Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Common Data for Question No. 3 & 4Air at 25°C approaches a 0.9 m long by 0.6 m wide flat plate with an approach velocity 4.5 m/sec. The plate is heated to a surface temperature of 135°C.It is given that at a temperature of 80°C, the thermo-physical properties of air arev = 21.07 x 10-6m2/sk = 0.0304 W/m-°CPr = 0.692Make calculations forThe local heat transfer coefficient at a distance of 0.5 m from the leading edge is __________Correct answer is between '5.80,5.90'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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