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With a dynamic load capacity of 2.2 kN, a roller bearing can operate at 600 rpm for 2000 hours. Then its maximum radial load will be equal to
  • a)
    409.2 N
  • b)
    308.4 N
  • c)
    206.5 N
  • d)
    609.8 N
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
With a dynamic load capacity of 2.2 kN, a roller bearing can operate ...
Given: Dynamic load capacity (C) = 2.2 kN
Life of bearing (Lf) = 60 x N x time duration
= 60 x 600 x 2000
= 72 x 106 revolutions
Using the following relation,
K = Constant = 3.3
On solving, we get, w = 609.8 (approx)
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Most Upvoted Answer
With a dynamic load capacity of 2.2 kN, a roller bearing can operate ...
Given information:
- Dynamic load capacity of the roller bearing: 2.2 kN
- Operating speed of the roller bearing: 600 rpm
- Operating time: 2000 hours

Calculation:

Step 1: Convert the dynamic load capacity to N (Newtons)
- 1 kN is equal to 1000 N
- Therefore, the dynamic load capacity is equal to 2.2 kN * 1000 N/kN = 2200 N

Step 2: Calculate the total revolutions of the roller bearing
- The roller bearing operates at a speed of 600 rpm for 2000 hours
- Total revolutions = 600 rpm * 2000 hours = 1,200,000 revolutions

Step 3: Determine the maximum radial load
- The maximum radial load is given by the formula: Maximum radial load = (Dynamic load capacity / Square root of total revolutions)
- Maximum radial load = 2200 N / √1,200,000 revolutions
- Maximum radial load = 2200 N / 1095.45
- Maximum radial load ≈ 2.007 N

Answer:
Therefore, the maximum radial load of the roller bearing is approximately equal to 2.007 N, which is closest to option 'D' (609.8 N).
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With a dynamic load capacity of 2.2 kN, a roller bearing can operate at 600 rpm for 2000 hours. Then its maximum radial load will be equal toa) 409.2 Nb) 308.4 Nc) 206.5 Nd) 609.8 NCorrect answer is option 'D'. Can you explain this answer?
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