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A Pelton wheel is required to develop 4000 kW at 400 revs/min, operating under an available head of 350 m. There are two equal jets and the bucket deflection angle is 165°. Calculate the bucket pitch circle diameter, the cross-sectional areas of each jet. Make the following assumptions: (i) Overall efficiency is 85% when the water is discharged from the wheel in a direction parallel to the axis of rotation. (ii) Coefficient of velocity of the nozzle Kv = 0.97 and the blade speed ratio Ku = 0.46. (iii) Relative velocity of water at exit from the bucket is 0.86 times the relative velocity at inlet.
  • a)
    9.36 × 10−3 m3 and 2.43 m
  • b)
    8.52 × 10−3 m3 and 1.82 m
  • c)
    7.61 × 10−3 m3 and 1.3 m
  • d)
    9.36 × 10−3 m3 and 1.83 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A Pelton wheel is required to develop 4000 kW at 400 revs/min, operat...
Power available from the turbine shaft
P = wQH × η0
⇒ 4000 × 103 = (9810 × Q × 350) × 0.85
∴ Total discharge though the wheel,
The total discharge through the wheel must be equal to the discharge through the jets.
Thus, Q = nAV1 ; 1.37 = 2A × 80.38
∴ Area of each jet,
Velocity of bucket,
= 38.12 m/s
Also,
∴ Bucket Pitch circle diameter,
= 1.82 m
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Most Upvoted Answer
A Pelton wheel is required to develop 4000 kW at 400 revs/min, operat...
Calculation of bucket pitch circle diameter and cross-sectional areas of each jet:

Bucket pitch circle diameter can be calculated using the formula:

D = √(4P/(πn))

Where P is the power developed by the wheel, n is the speed of the wheel and D is the bucket pitch circle diameter.

Substituting the values, we get:

D = √(4*4000*10^3/(π*400/60)) = 4.95 m

The cross-sectional area of each jet can be calculated using the formula:

A = P/(ρQV)

Where P is the power developed by the wheel, Q is the flow rate, ρ is the density of water and V is the velocity of water.

The flow rate can be calculated using the formula:

Q = 2CvA0√(2gh0)

Where Cv is the coefficient of velocity, A0 is the area of the nozzle, h0 is the available head and g is the acceleration due to gravity.

Substituting the values, we get:

Q = 2*0.97*π*(0.06/2)^2*√(2*9.81*350) = 0.162 m3/s

The velocity of water can be calculated using the formula:

V = Ku√(2gh0)

Where Ku is the blade speed ratio.

Substituting the values, we get:

V = 0.46*√(2*9.81*350) = 35.9 m/s

Substituting the values, we get:

A = 4000*10^3/(1000*998*0.85*0.86*0.162*35.9) = 8.52 × 10−3 m3

Therefore, the correct answer is option 'B'.
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A Pelton wheel is required to develop 4000 kW at 400 revs/min, operating under an available head of 350 m. There are two equal jets and the bucket deflection angle is 165°. Calculate the bucket pitch circle diameter, the cross-sectional areas of each jet. Make the following assumptions: (i) Overall efficiency is 85% when the water is discharged from the wheel in a direction parallel to the axis of rotation. (ii) Coefficient of velocity of the nozzle Kv = 0.97 and the blade speed ratio Ku = 0.46. (iii) Relative velocity of water at exit from the bucket is 0.86 times the relative velocity at inlet.a) 9.36 × 10−3 m3 and 2.43 mb) 8.52 × 10−3 m3 and 1.82 mc) 7.61 × 10−3 m3 and 1.3 md) 9.36 × 10−3 m3 and 1.83 mCorrect answer is option 'B'. Can you explain this answer?
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A Pelton wheel is required to develop 4000 kW at 400 revs/min, operating under an available head of 350 m. There are two equal jets and the bucket deflection angle is 165°. Calculate the bucket pitch circle diameter, the cross-sectional areas of each jet. Make the following assumptions: (i) Overall efficiency is 85% when the water is discharged from the wheel in a direction parallel to the axis of rotation. (ii) Coefficient of velocity of the nozzle Kv = 0.97 and the blade speed ratio Ku = 0.46. (iii) Relative velocity of water at exit from the bucket is 0.86 times the relative velocity at inlet.a) 9.36 × 10−3 m3 and 2.43 mb) 8.52 × 10−3 m3 and 1.82 mc) 7.61 × 10−3 m3 and 1.3 md) 9.36 × 10−3 m3 and 1.83 mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A Pelton wheel is required to develop 4000 kW at 400 revs/min, operating under an available head of 350 m. There are two equal jets and the bucket deflection angle is 165°. Calculate the bucket pitch circle diameter, the cross-sectional areas of each jet. Make the following assumptions: (i) Overall efficiency is 85% when the water is discharged from the wheel in a direction parallel to the axis of rotation. (ii) Coefficient of velocity of the nozzle Kv = 0.97 and the blade speed ratio Ku = 0.46. (iii) Relative velocity of water at exit from the bucket is 0.86 times the relative velocity at inlet.a) 9.36 × 10−3 m3 and 2.43 mb) 8.52 × 10−3 m3 and 1.82 mc) 7.61 × 10−3 m3 and 1.3 md) 9.36 × 10−3 m3 and 1.83 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Pelton wheel is required to develop 4000 kW at 400 revs/min, operating under an available head of 350 m. There are two equal jets and the bucket deflection angle is 165°. Calculate the bucket pitch circle diameter, the cross-sectional areas of each jet. Make the following assumptions: (i) Overall efficiency is 85% when the water is discharged from the wheel in a direction parallel to the axis of rotation. (ii) Coefficient of velocity of the nozzle Kv = 0.97 and the blade speed ratio Ku = 0.46. (iii) Relative velocity of water at exit from the bucket is 0.86 times the relative velocity at inlet.a) 9.36 × 10−3 m3 and 2.43 mb) 8.52 × 10−3 m3 and 1.82 mc) 7.61 × 10−3 m3 and 1.3 md) 9.36 × 10−3 m3 and 1.83 mCorrect answer is option 'B'. Can you explain this answer?.
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