If log2x log4x log16x=21/4 these x is equal to?
Solution:
Given equation: log2x log4x log16x=21/4
To solve this equation for x, we will use the properties of logarithms and simplify the equation.
Step 1: Simplify the logarithms
We know that loga + logb = log(ab). Using this property, we can simplify the first two logarithms in the equation.
log2x + log4x = log(2x * 4x) = log(8x^2)
Now, we can rewrite the equation as:
log(8x^2) log16x = 21/4
Step 2: Simplify the logarithms further
We know that loga - logb = log(a/b). Using this property, we can simplify the left-hand side of the equation.
log(8x^2/16x) = log(x/2)
Now, the equation becomes:
log(x/2) = 21/4
Step 3: Solve for x
We know that loga(b) = c is equivalent to b = a^c. Using this property, we can solve for x.
x/2 = 2^(21/4)
x = 2^(21/4 + 1)
x = 2^(25/4)
x = 32
Therefore, x is equal to 32.
Final Answer: x = 32
If log2x log4x log16x=21/4 these x is equal to?
Log 2 X + Log 2^2 X + Log 2^4 X =21/4
1log 2 X + 1/2Log 2 X + 1/4Log 2 X =21/4
lets take a common (Log 2 X) then.
(1+1/2+1/4)Log 2 X = 21/4
7/4 Log 2 X = 21/4
log 2 X = 21/4 × 4/7
Log 2 X = 3
(2)^3 =8
Ans is 8....