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If logx to base 2 logx to base 4 logx to base 16= 21/4 these x is equal to?
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If logx to base 2 logx to base 4 logx to base 16= 21/4 these x is ...
Solution:


Step 1: Convert logx to base 4 into logx to base 2


Since we need to find logx to base 2, we can convert logx to base 4 into logx to base 2 using the following formula:


logx to base 4 = logx to base 2 / log4 to base 2


Substituting the values given in the question, we get:


logx to base 4 = logx to base 2 / 2


Therefore, logx to base 2 = 2*logx to base 4


Step 2: Convert logx to base 16 into logx to base 2


Using the same formula as in step 1, we can convert logx to base 16 into logx to base 2:


logx to base 16 = logx to base 2 / log16 to base 2


Substituting the values given in the question, we get:


logx to base 16 = logx to base 2 / 4


Therefore, logx to base 2 = 4*logx to base 16


Step 3: Combine the equations


Now we can substitute the two equations we derived in steps 1 and 2 into the equation given in the question:


logx to base 2 + 2*logx to base 4 + 4*logx to base 16 = 21/4


Substituting the values we derived in steps 1 and 2, we get:


logx to base 2 + 2*(logx to base 2 / 2) + 4*(logx to base 2 / 4) = 21/4


Simplifying, we get:


logx to base 2 + logx to base 2 + logx to base 2 = 21/4


3*logx to base 2 = 21/4


logx to base 2 = 7/4


Step 4: Find x


Now we can use the definition of logarithms to find x:


x = 2^(logx to base 2)


Substituting the value we found in step 3, we get:


x = 2^(7/4)


Therefore, x = 5.66 (approx)


Answer:


The value of x is 5.66 (approx).
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If logx to base 2 logx to base 4 logx to base 16= 21/4 these x is equal to?
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