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X varies inversely as square of y and given that y=2 for x=1 the value of x for y is 6?
Verified Answer
X varies inversely as square of y and given that y=2 for x=1 the value...
No, the value of x for y = 6 is not 1.
The equation for an inverse variation is xy^2 = k, where k is a constant.
For x = 1 and y = 2, we have 1 * 22^2 = k, so k = 4.
Therefore, the equation is xy� = 4.
For y = 6, we need to solve for x:
x(6)^2 = 4
x = 4/36
x = 1/9
Therefore, the value of x for y = 6 is 1/9.
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Most Upvoted Answer
X varies inversely as square of y and given that y=2 for x=1 the value...
Given:

X varies inversely as the square of y.

To find:

The value of x when y is 6.

Explanation:

Understanding Inverse Variation:

Inverse variation, also known as inverse proportion, is a relationship between two variables where an increase in one variable leads to a decrease in the other variable, and vice versa. Mathematically, if two variables x and y vary inversely, their relationship can be represented as:

x = k/y

Where k is the constant of variation.

Using the Given Information:

We are given that x varies inversely as the square of y. This can be represented as:

x = k/y^2

To find the value of k, we can use the given values of x and y when they are in a direct variation. We are given that when y = 2, x = 1. Substituting these values into the equation, we get:

1 = k/2^2
1 = k/4
k = 4

Finding the Value of x:

Now that we have the value of k, we can substitute it back into the equation:

x = 4/y^2

To find the value of x when y = 6, we substitute y = 6 into the equation:

x = 4/6^2
x = 4/36
x = 1/9

So, when y is 6, the value of x is 1/9.
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X varies inversely as square of y and given that y=2 for x=1 the value of x for y is 6?
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