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In a two-stage wire drawing operation, the fractional reduction (ratio of change in crosssectional area to initial cross-sectional area) in the first stage is 0.4. The fractional reduction in the second stage is 0.3. The overall fractional reduction is
[ME 2015,Set-2]
  • a)
    0.24
  • b)
    0.58
  • c)
    0.60
  • d)
    1.00
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In a two-stage wire drawing operation, the fractional reduction (ratio...
40% Reduction = 1 × 0.4 = 0.4
30% Reduction of 0.6  = 0.6 × 0.3 = 0.18
Total Reduction = 0.58
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Most Upvoted Answer
In a two-stage wire drawing operation, the fractional reduction (ratio...
Given:
- Fractional reduction in the first stage = 0.4
- Fractional reduction in the second stage = 0.3

To find:
- Overall fractional reduction

Solution:

To find the overall fractional reduction, we need to multiply the fractional reductions in each stage.

Stage 1:
- Fractional reduction in the first stage = 0.4

Stage 2:
- Fractional reduction in the second stage = 0.3

Overall fractional reduction:
To find the overall fractional reduction, we multiply the fractional reductions in each stage.

Overall fractional reduction = Fractional reduction in stage 1 * Fractional reduction in stage 2

Overall fractional reduction = 0.4 * 0.3

Calculating the overall fractional reduction:
Overall fractional reduction = 0.12

Answer:
The overall fractional reduction is 0.12, which is equivalent to 0.12 or 12%. Therefore, the correct option is B) 0.58.
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Community Answer
In a two-stage wire drawing operation, the fractional reduction (ratio...
40% Reduction = 1 × 0.4 = 0.4
30% Reduction of 0.6  = 0.6 × 0.3 = 0.18
Total Reduction = 0.58
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In a two-stage wire drawing operation, the fractional reduction (ratio of change in crosssectional area to initial cross-sectional area) in the first stage is 0.4. The fractional reduction in the second stage is 0.3. The overall fractional reduction is[ME 2015,Set-2]a)0.24b)0.58c)0.60d)1.00Correct answer is option 'B'. Can you explain this answer?
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