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By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer?.

Solutions for By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer?, a detailed solution for By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice By application of tensile force, the crosssectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in crosssectional area by 50% in a single step by applying tensile force.After deformation, the true strain in bar P and bar Q will, respectively be[PI 2008]a)0.5 and 0.5b)0.58 and 0.69c)0.69 and 0.69d)0.78 and 1.00Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.