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A wire of 0.1 mm dia is drawn from a rod of 15 mm diameter dies giving reductions of 20%, 40% and 80% are available. For minimum error in the final size, the number of stages and reduction at each stage respectively would be
[ME 1996]
  • a)
    3 stages and 80% reduction for all three stages
  • b)
    4 stages and 80% reduction for first three stages followed by a finishing stage of 20% reduction
  • c)
    5 stage and reduction of 80%, 80%, 40%, 40%, 20% is sequence
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A wire of 0.1 mm dia is drawn from a rod of 15 mm diameter dies giving...
d1 = 0.2d0 Given, d0 = 15 mm, we get d1 = 3 mm
Similarly, after 2nd pass, we get d2 = 0.6 mm and after 3rd pass, we get d3 = 0.12 mm For option (b), 1st 3 stages are same as in option (a), in 4th pass we have

⇒ d5 = 0.8 d4 = 0.8 × 0.216 = 0.1728 mm
Ouptput in option (b) is closest to the desired diameter of 0.1 mm.
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Most Upvoted Answer
A wire of 0.1 mm dia is drawn from a rod of 15 mm diameter dies giving...
Given:
- Diameter of the wire before drawing = 0.1 mm
- Diameter of the rod = 15 mm
- Reductions available = 20%, 40%, and 80%

To find:
The number of stages and reduction at each stage for minimum error in the final size.

Solution:
To minimize the error in the final size, we need to ensure that the reduction at each stage is as small as possible. Let's analyze the given options to determine the best approach.

Option A:
3 stages and 80% reduction for all three stages
- In this option, the reduction at each stage is 80%, which is a large reduction. This would result in a significant error in the final size. Therefore, this option is not the best choice.

Option B:
4 stages and 80% reduction for the first three stages followed by a finishing stage of 20% reduction
- In this option, the first three stages have a reduction of 80%, which is a large reduction. However, the final stage has a reduction of only 20%, which is a smaller reduction. This finishing stage helps to minimize the error in the final size. Therefore, this option is a better choice compared to option A.

Option C:
5 stages and reduction of 80%, 80%, 40%, 40%, 20% is sequenced
- In this option, the first two stages have a reduction of 80%, which is a large reduction. The next two stages have a reduction of 40%, which is smaller. The final stage has a reduction of 20%, which is the smallest reduction. This option also helps to minimize the error in the final size. However, it involves more stages compared to option B. Therefore, option B is a better choice.

Conclusion:
The best approach for minimum error in the final size is option B, which involves 4 stages with an 80% reduction for the first three stages followed by a finishing stage of 20% reduction.
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A wire of 0.1 mm dia is drawn from a rod of 15 mm diameter dies giving reductions of 20%, 40% and 80% are available. For minimum error in the final size, the number of stages and reduction at each stage respectively would be[ME 1996]a)3 stages and 80% reduction for all three stagesb)4 stages and 80% reduction for first three stages followed by a finishing stage of 20% reductionc)5 stage and reduction of 80%, 80%, 40%, 40%, 20% is sequenced)None of theseCorrect answer is option 'B'. Can you explain this answer?
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