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In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will be
- a)1010 kHz
- b)1455 kHz
- c)1910 kHz
- d)545 kHz
Correct answer is option 'C'. Can you explain this answer?
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In a broadcast superheterodynes receiver having no RF amplifier, the l...
Calculation of Image Frequency in a Superheterodyne Receiver
Introduction:
In a superheterodyne receiver, the incoming RF signal is mixed with a local oscillator (LO) signal to produce an intermediate frequency (IF) signal. The IF signal is then amplified and detected to recover the original modulating signal.
Given:
Loaded Q of the antenna coupling circuit = 100
Intermediate frequency (IF) = 455 kHz
RF frequency (fRF) = 1000 kHz
Formula:
Image frequency (fIMG) = 2 x fIF - fRF
Calculation:
The resonant frequency of the antenna coupling circuit can be calculated as follows:
fR = fRF / (1 + Q)
Substituting the given values, we get:
fR = 1000 kHz / (1 + 100) = 9.9 kHz
The upper and lower frequency limits of the image frequency can be calculated as follows:
fIMG(upper) = fIF + fR = 464.9 kHz
fIMG(lower) = fIF - fR = 445.1 kHz
Substituting the given values, we get:
fIMG = 2 x 455 kHz - 1000 kHz = 910 kHz
Since the image frequency is higher than the upper limit of 464.9 kHz, it lies beyond the tuning range of the receiver. Therefore, the image frequency that is within the tuning range of the receiver is:
fIMG = 2 x 455 kHz - 1000 kHz = 910 kHz + 1000 kHz = 1910 kHz
Hence, the correct answer is option (C) 1910 kHz.
Introduction:
In a superheterodyne receiver, the incoming RF signal is mixed with a local oscillator (LO) signal to produce an intermediate frequency (IF) signal. The IF signal is then amplified and detected to recover the original modulating signal.
Given:
Loaded Q of the antenna coupling circuit = 100
Intermediate frequency (IF) = 455 kHz
RF frequency (fRF) = 1000 kHz
Formula:
Image frequency (fIMG) = 2 x fIF - fRF
Calculation:
The resonant frequency of the antenna coupling circuit can be calculated as follows:
fR = fRF / (1 + Q)
Substituting the given values, we get:
fR = 1000 kHz / (1 + 100) = 9.9 kHz
The upper and lower frequency limits of the image frequency can be calculated as follows:
fIMG(upper) = fIF + fR = 464.9 kHz
fIMG(lower) = fIF - fR = 445.1 kHz
Substituting the given values, we get:
fIMG = 2 x 455 kHz - 1000 kHz = 910 kHz
Since the image frequency is higher than the upper limit of 464.9 kHz, it lies beyond the tuning range of the receiver. Therefore, the image frequency that is within the tuning range of the receiver is:
fIMG = 2 x 455 kHz - 1000 kHz = 910 kHz + 1000 kHz = 1910 kHz
Hence, the correct answer is option (C) 1910 kHz.
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In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer?
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In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer?.
In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 1000 kHz will bea)1010 kHzb)1455 kHzc)1910 kHzd)545 kHzCorrect answer is option 'C'. Can you explain this answer?.
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