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A truss consists of horizontal members (AC, CD, DB  and EF) and vertical members (CE and DF) having length l each. The-members AE, DE and BF are inclined at 45° to the horizontal For the uniformly distributed load p per unit length on the members EF of the truss shown in figure given below, the force in the member CD is
[2003]
  • a)
    pl/2
  • b)
    pl
  • c)
    0
  • d)
    2pl/3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A truss consists of horizontal members (AC, CD, DB and EF) and vertica...
Total load on EF member = pl
where l = length of EF
For horizontal equilibrium
RA + RB = Pl

Taking moment about A, we have

Considering a point A.
For horizontal equilibrium FAC + FAE cos 45º = 0

For vertical equilibrium
RA – FAE sin 45º = 0


–ve sign shows that the force on member AC is opposite of assumed. Now considering a point C For horizontal equilibrium
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Most Upvoted Answer
A truss consists of horizontal members (AC, CD, DB and EF) and vertica...
Total load on EF member = pl
where l = length of EF
For horizontal equilibrium
RA + RB = Pl

Taking moment about A, we have

Considering a point A.
For horizontal equilibrium FAC + FAE cos 45º = 0

For vertical equilibrium
RA – FAE sin 45º = 0


–ve sign shows that the force on member AC is opposite of assumed. Now considering a point C For horizontal equilibrium
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Community Answer
A truss consists of horizontal members (AC, CD, DB and EF) and vertica...
Total load on EF member = pl
where l = length of EF
For horizontal equilibrium
RA + RB = Pl

Taking moment about A, we have

Considering a point A.
For horizontal equilibrium FAC + FAE cos 45º = 0

For vertical equilibrium
RA – FAE sin 45º = 0


–ve sign shows that the force on member AC is opposite of assumed. Now considering a point C For horizontal equilibrium
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A truss consists of horizontal members (AC, CD, DB and EF) and vertical members (CE and DF) having length l each. The-members AE, DE and BF are inclined at 45° to the horizontal For the uniformly distributed load p per unit length on the members EF of the truss shown in figure given below, the force in the member CD is[2003]a)pl/2b)plc)0d)2pl/3Correct answer is option 'A'. Can you explain this answer?
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