A can do some work in 24 days, B can do it in 32 days and C can do it ...
Solution:
Given, A can do the work in 24 days, B can do it in 32 days, and C can do it in 60 days.
Let the total work be 240 units.
Let the efficiency of A, B, and C be a, b, and c respectively.
Then, a = 240/24 = 10 units/day
b = 240/32 = 7.5 units/day
c = 240/60 = 4 units/day
Calculation of work done by A, B, and C in 6 and 8 days
Let x be the number of days taken to complete the work.
Let A work for 6 days and B work for 8 days.
Total work done by A and B in 6 days = 6a + 8b = 6(10) + 8(7.5) = 90 units
Remaining work = 240 - 90 = 150 units
Total work done by A, B, and C in x days = xa + (x-6)b + (x-14)c
= x(10) + (x-6)(7.5) + (x-14)(4)
= 10x + 7.5x - 45 + 4x - 56
= 21.5x - 101
Calculation of remaining work
As per the given question, A left after 6 days and B left after 8 days. Therefore, the remaining work is done by C.
Work done by C in (x-14) days = (x-14)c = (x-14)(4) units
Calculation of total work done
Total work done = Work done by A + Work done by B + Work done by C
= 6a + 8b + (x-14)c
= 60 + 60 + 4x - 56
= 4x + 4
Calculation of x
Total work done = 240 units
4x + 4 = 240
4x = 236
x = 59
Therefore, the whole work will be completed in 59 days.
Answer: Option A (35) is incorrect. Option B (30) is incorrect. Option C (22) is incorrect. Option D (20) is incorrect.