*315. The time required to empty a concrete tank through a rectangular...
Solution:
Given data:
Head at the start of emptying = 16 cm
Head at the end of emptying = 8 cm
Time taken to empty the tank = 16 minutes
To find:
Time required to empty the tank up to the crest
Assumptions made:
The flow through the rectangular weir is steady and incompressible.
The cross-section of the tank remains the same throughout the emptying process.
Calculation:
Let Q1 be the discharge through the rectangular weir when the head is 16 cm.
Let Q2 be the discharge through the rectangular weir when the head is 8 cm.
Let t1 be the time taken to empty the tank from 16 cm to 8 cm.
Let t2 be the time required to empty it further up to the crest.
From the Francis formula, we know that:
Q = CLH^1.5
where Q = discharge, C = coefficient of discharge, L = length of the weir crest, and H = head over the crest.
Since the crest length remains the same, we can write:
Q1 = CL(16)^1.5
Q2 = CL(8)^1.5
Dividing the two equations, we get:
Q1/Q2 = (16/8)^1.5
Q1/Q2 = 2.828
We also know that:
Q = AV
where A = area of cross-section of the tank and V = velocity of water.
Since the cross-sectional area remains the same, we can write:
Q1 = AV1
Q2 = AV2
Dividing the two equations, we get:
Q1/Q2 = V1/V2
Using the continuity equation, we know that:
A1V1 = A2V2
Substituting the above equation in the previous equation, we get:
Q1/Q2 = A2/A1
Since the cross-sectional area remains the same, we can write:
Q1/Q2 = 1
Comparing this with the previous result, we get:
2.828 = 1
This is not possible, which means our assumption that the cross-sectional area remains the same is wrong.
Therefore, the time required to empty the tank up to the crest is infinite.
Answer: d) infinite.
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