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In Y.D.S.E. using light of wavelength 6000Å angular fringe width of fringe formed on the screen is 1°. Find the distance between the slits :-
    Correct answer is '0.03'. Can you explain this answer?
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    In Y.D.S.E. using light of wavelength 6000Å angular fringe width...
    Given data:
    - Wavelength of light (λ) = 6000 Å
    - Angular fringe width (θ) = 1°

    Formula:
    - Angular fringe width (θ) = λ / d
    - where d is the distance between the slits

    Solution:
    - Convert the wavelength of light from Ångström to meters: 6000 Å = 6000 x 10^-10 m = 6 x 10^-7 m

    Calculate the distance between the slits:
    - θ = λ / d
    - 1° = 6 x 10^-7 m / d
    - d = 6 x 10^-7 m / 1°
    - d = 6 x 10^-7 m / (π/180)
    - d = 6 x 10^-7 m x 180 / π
    - d ≈ 0.03 m
    Therefore, the distance between the slits is approximately 0.03 meters.
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    In Y.D.S.E. using light of wavelength 6000Å angular fringe width of fringe formed on the screen is 1°. Find the distance between the slits :-Correct answer is '0.03'. Can you explain this answer?
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