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If a, b are odd integers then number of integral root, of equation x10 + ax9 + b = 0 is equal to :
    Correct answer is '0'. Can you explain this answer?
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    If a, b are odd integers then number of integral root, of equation x10...
    Let P is a root (∈I)
    Case-I : p is odd
    p10 + ap9 + b ≠ 0
    Because LHS odd
    Case-II : p is even
    p10 + ap9 + b ≠ 0
    because, LHs is odd
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    Most Upvoted Answer
    If a, b are odd integers then number of integral root, of equation x10...
    Let P is a root (∈I)
    Case-I : p is odd
    p10 + ap9 + b ≠ 0
    Because LHS odd
    Case-II : p is even
    p10 + ap9 + b ≠ 0
    because, LHs is odd
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    Community Answer
    If a, b are odd integers then number of integral root, of equation x10...
    Introduction:
    We are given the equation x^10 + ax^9 + b = 0, where a and b are odd integers. We need to find the number of integral roots of this equation.

    Assumption:
    Let's assume that the equation has at least one integral root.

    Analysis:
    If the equation has an integral root, say r, then it implies that r^10 + ar^9 + b = 0.
    - As a and b are odd integers, r^10 and ar^9 will also be odd.
    - The sum of two odd numbers is always even.
    - Therefore, the sum of r^10, ar^9, and b will be even.

    Contradiction:
    However, we know that the sum of two even numbers can never be equal to zero.
    - This contradicts our assumption that the equation has an integral root.
    - Therefore, the equation x^10 + ax^9 + b = 0 does not have any integral roots.

    Conclusion:
    The correct answer is 0, which means there are no integral roots for the given equation.
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    If a, b are odd integers then number of integral root, of equation x10+ ax9+ b = 0 is equal to :Correct answer is '0'. Can you explain this answer?
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