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Of the three numbers, the first is one third of the second and twice the third. The average of these numbers is 27. The largest of these numbers is
  • a)
    18
  • b)
    36
  • c)
    54
  • d)
    108
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Of the three numbers, the first is one third of the second and twice ...
Let the three numbers be a' b' c
Now a = b/3 a = 2c
Also (a+b+c)/3 = 27
Hence solving the equations: a = 18, b = 54, c = 9
Largest of three is 54.
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Of the three numbers, the first is one third of the second and twice the third. The average of these numbers is 27. The largest of these numbers isa)18b)36c)54d)108Correct answer is option 'C'. Can you explain this answer?
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