JEE Exam > JEE Questions > What will be the resultant pH when 150 mL of ...
Start Learning for Free
What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH (pH = 12.0)?
Correct answer is '11.6'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
What will be the resultant pH when 150 mL of an aqueous solution of HC...
Most Upvoted Answer
What will be the resultant pH when 150 mL of an aqueous solution of HC...
Given:
- Volume of HCl solution (V1) = 150 mL
- pH of HCl solution = 2.0
- Volume of NaOH solution (V2) = 350 mL
- pH of NaOH solution = 12.0
To find:
The resultant pH when the two solutions are mixed.
Solution:
Step 1: Calculate the moles of each solution
For HCl:
Moles of HCl = Molarity of HCl × Volume of HCl / 1000
Given that the pH of HCl solution is 2.0, we can find the concentration of HCl using the formula:
pH = -log[H+]
2.0 = -log[H+]
[H+] = 10^(-pH)
[H+] = 10^(-2) = 0.01 M
Moles of HCl = 0.01 × 150 / 1000 = 0.0015 moles
For NaOH:
Moles of NaOH = Molarity of NaOH × Volume of NaOH / 1000
Given that the pH of NaOH solution is 12.0, we can find the concentration of NaOH using the formula:
pOH = -log[OH-]
pOH = 14 - pH = 14 - 12 = 2
[OH-] = 10^(-pOH) = 10^(-2) = 0.01 M
Moles of NaOH = 0.01 × 350 / 1000 = 0.0035 moles
Step 2: Determine the moles of H+ and OH- ions
The reaction between HCl and NaOH is:
HCl + NaOH → NaCl + H2O
From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of water.
Since the moles of HCl and NaOH are in the ratio 1:1, the moles of H+ and OH- ions will also be in the ratio 1:1.
Therefore, the moles of H+ ions = 0.0015 moles
And the moles of OH- ions = 0.0035 moles
Step 3: Calculate the concentration of H+ and OH- ions
Concentration of H+ ions = Moles of H+ ions / Total volume of solution (V1 + V2)
Concentration of H+ ions = 0.0015 / (150 + 350) = 0.0015 / 500 = 0.003 M
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer?
Question Description
What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer?.
What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer?.
Solutions for What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer?, a detailed solution for What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? has been provided alongside types of What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH = 12.0)?Correct answer is '11.6'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup