pH of a solution produced when an aqueous solution of pH = 6 is mixed ...
pH of a solution produced when an aqueous solution of pH = 6 is mixed with an equal volume of an aqueous solution of pH = 3 is about:
Explanation:
When two solutions are mixed, the resulting pH can be calculated using the formula:
pH = -log[H+]
Where [H+] is the concentration of hydrogen ions in the solution.
Step 1: Convert the pH values to [H+] values.
For pH = 6:
[H+] = 10^-6 = 0.000001
For pH = 3:
[H+] = 10^-3 = 0.001
Step 2: Calculate the concentration of hydrogen ions in the resulting solution.
When two solutions of equal volume are mixed, the resulting concentration of hydrogen ions can be calculated using the formula:
[H+] resulting = ( [H+]1 * V1 + [H+]2 * V2 ) / ( V1 + V2 )
Where [H+]1 and [H+]2 are the concentrations of hydrogen ions in the original solutions, and V1 and V2 are the volumes of the original solutions.
In this case, the volumes of the original solutions are equal, so the formula simplifies to:
[H+] resulting = ( [H+]1 + [H+]2 ) / 2
Substituting the values:
[H+] resulting = ( 0.000001 + 0.001 ) / 2 = 0.000501
Step 3: Calculate the pH of the resulting solution using the [H+] resulting value.
pH resulting = -log(0.000501) ≈ 3.3
Therefore, the pH of the resulting solution is approximately 3.3.
Conclusion:
The correct answer is option A) 3.3.