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500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml?
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500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution...
Calculation of Final Volume and Molality of NaCl in Final Solution
Step 1: Calculate the total amount of NaCl in the initial solution.
Total amount of NaCl in the initial solution = (500 ml x 2 M) + (200 ml x 2 M)
Total amount of NaCl in the initial solution = 2000 mmol
Step 2: Calculate the total volume of the final solution.
Total volume of the final solution = 500 ml + 200 ml
Total volume of the final solution = 700 ml
Step 3: Calculate the molality of NaCl in the final solution.
Molality is defined as the number of moles of solute per kilogram of solvent.
Therefore, we need to first calculate the mass of the final solution using its density.
Mass of the final solution = volume of the final solution x density of the final solution
Mass of the final solution = 700 ml x 1.5 g/ml
Mass of the final solution = 1050 g
Now, we can calculate the molality of NaCl in the final solution.
Molality of NaCl in the final solution = (total amount of NaCl in the initial solution) / (mass of the final solution in kg)
Molality of NaCl in the final solution = 2000 mmol / (1050 g / 1000)
Molality of NaCl in the final solution = 1.90 m
Step 4: Conclusion
The final volume of the solution is 700 ml and the molality of NaCl in the final solution is 1.90 m.
Step 1: Calculate the total amount of NaCl in the initial solution.
Total amount of NaCl in the initial solution = (500 ml x 2 M) + (200 ml x 2 M)
Total amount of NaCl in the initial solution = 2000 mmol
Step 2: Calculate the total volume of the final solution.
Total volume of the final solution = 500 ml + 200 ml
Total volume of the final solution = 700 ml
Step 3: Calculate the molality of NaCl in the final solution.
Molality is defined as the number of moles of solute per kilogram of solvent.
Therefore, we need to first calculate the mass of the final solution using its density.
Mass of the final solution = volume of the final solution x density of the final solution
Mass of the final solution = 700 ml x 1.5 g/ml
Mass of the final solution = 1050 g
Now, we can calculate the molality of NaCl in the final solution.
Molality of NaCl in the final solution = (total amount of NaCl in the initial solution) / (mass of the final solution in kg)
Molality of NaCl in the final solution = 2000 mmol / (1050 g / 1000)
Molality of NaCl in the final solution = 1.90 m
Step 4: Conclusion
The final volume of the solution is 700 ml and the molality of NaCl in the final solution is 1.90 m.
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500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution...
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500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml?
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500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml?.
500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 500 ml of 2 M NaCl solution was mixed with 200 ml of 2 M NaCl solution.Calculate the final volume and molality of NaCl in final solution if final solution has density of 1.5 g/ml?.
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