Divide 30 into 5 parts in ap whose sum is 69 and product of first two ...
Dividing 30 into 5 parts in AP
To divide 30 into 5 parts in AP, we need to find the common difference between the terms and then determine each term. Let's call the first term a and the common difference d.
Finding the common difference
Since we have 5 terms, we can use the formula for the sum of an AP to find the value of d. The sum of an AP is given by:
S = n/2(2a + (n-1)d)
where S is the sum of the AP, n is the number of terms, a is the first term, and d is the common difference.
Substituting n = 5 and S = 69, we get:
69 = 5/2(2a + 4d)
13.8 = 2a + 4d
2a = 13.8 - 4d
a = (13.8 - 4d)/2
Now we need to find the value of d. We know that the product of the first two terms is 483. So,
a(a+d) = 483
Substituting a = (13.8 - 4d)/2, we get:
(13.8 - 4d)/2[(13.8 - 4d)/2 + d] = 483
27.6 - 8d + 2d^2 = 1932
2d^2 - 8d - 1904.4 = 0
Solving for d, we get d = 7.4 or d = -51.4. Since the common difference cannot be negative, we take d = 7.4.
Finding the terms
Now that we have the value of the common difference, we can find the value of the first term:
a = (13.8 - 4d)/2 = (13.8 - 4(7.4))/2 = -1.4
So the terms are:
-1.4, 6, 13.4, 20.8, 28.2
These are the 5 parts into which 30 can be divided in AP whose sum is 69 and product of first two is 483.