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Divide 30 into 5 parts in ap whose sum is 69 and product of first two is 483 numbers are?
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Divide 30 into 5 parts in ap whose sum is 69 and product of first two ...
Dividing 30 into 5 parts in AP


To divide 30 into 5 parts in AP, we need to find the common difference between the terms and then determine each term. Let's call the first term a and the common difference d.


Finding the common difference


Since we have 5 terms, we can use the formula for the sum of an AP to find the value of d. The sum of an AP is given by:


S = n/2(2a + (n-1)d)


where S is the sum of the AP, n is the number of terms, a is the first term, and d is the common difference.


Substituting n = 5 and S = 69, we get:


69 = 5/2(2a + 4d)


13.8 = 2a + 4d


2a = 13.8 - 4d


a = (13.8 - 4d)/2


Now we need to find the value of d. We know that the product of the first two terms is 483. So,


a(a+d) = 483


Substituting a = (13.8 - 4d)/2, we get:


(13.8 - 4d)/2[(13.8 - 4d)/2 + d] = 483


27.6 - 8d + 2d^2 = 1932


2d^2 - 8d - 1904.4 = 0


Solving for d, we get d = 7.4 or d = -51.4. Since the common difference cannot be negative, we take d = 7.4.


Finding the terms


Now that we have the value of the common difference, we can find the value of the first term:


a = (13.8 - 4d)/2 = (13.8 - 4(7.4))/2 = -1.4


So the terms are:


-1.4, 6, 13.4, 20.8, 28.2


These are the 5 parts into which 30 can be divided in AP whose sum is 69 and product of first two is 483.
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Divide 30 into 5 parts in ap whose sum is 69 and product of first two is 483 numbers are?
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