**Parallel Plate Air Capacitor Immersed in Oil**

A parallel plate capacitor consists of two parallel conductive plates separated by a dielectric material. In this case, the capacitor is immersed in oil, which has a dielectric constant of 2. We need to determine the electric field between the plates in this scenario.

**Dielectric Constant and Electric Field**

The dielectric constant, also known as the relative permittivity, is a measure of how effectively a material can store electrical energy in an electric field. It is denoted by the symbol "k" and is defined as the ratio of the electric field in vacuum to the electric field in the material.

The electric field between the plates of a parallel plate capacitor is given by the equation:

E = V / d,

where E is the electric field, V is the voltage across the plates, and d is the distance between the plates.

**Effect of Dielectric Material**

When a dielectric material is inserted between the plates of a capacitor, the electric field is reduced compared to the case of a vacuum. The electric field is inversely proportional to the dielectric constant of the material. Therefore, when the dielectric constant increases, the electric field decreases.

In this case, the dielectric constant of the oil is 2. Therefore, the electric field between the plates of the capacitor immersed in oil will be half of the electric field in a vacuum.

**Explanation in Detail**

1. **Electric Field Equation**: The electric field between the plates of a parallel plate capacitor is given by the equation E = V / d, where E is the electric field, V is the voltage across the plates, and d is the distance between the plates.

2. **Effect of Dielectric Material**: When a dielectric material is inserted between the plates of a capacitor, the electric field is reduced compared to the case of a vacuum. The electric field is inversely proportional to the dielectric constant of the material.

3. **Dielectric Constant of Oil**: In this scenario, the capacitor is immersed in oil, which has a dielectric constant of 2. Therefore, the electric field between the plates will be half of the electric field in a vacuum.

4. **Calculation**: If we assume that the electric field between the plates in a vacuum is E0, then the electric field in the oil will be E = E0 / 2.

5. **Example**: For example, if the electric field between the plates in a vacuum is 100 V/m, then the electric field in the oil will be 50 V/m.

Therefore, the electric field between the plates of the parallel plate air capacitor immersed in oil with a dielectric constant of 2 is reduced to half of the electric field in a vacuum.

Decreased 2 time