In the adjoining figure ACB is a quadrant with radius 'a'. A semicircl...
Problem Statement:
In the adjoining figure ACB is a quadrant with radius 'a'. A semicircle is drawn outside the quadrant taking AB as a diameter. Find the area of shaded region can not be :? Explain in details.
Solution:
Let's first identify the shaded region in the given figure:
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The shaded region is the area between the quadrant ACB and the semicircle ADB.
Step 1: Find the Area of the Quadrant ACB
The area of a quadrant of a circle with radius 'a' is given by:
Area of Quadrant ACB = 1/4 * π * a²
Step 2: Find the Area of the Semicircle ADB
The area of a semicircle with diameter 'd' is given by:
Area of Semicircle ADB = 1/2 * π * (AB/2)²
Here, AB is the diameter of the semicircle and is equal to the radius of the quadrant, which is 'a'.
Therefore, the area of the semicircle ADB is:
Area of Semicircle ADB = 1/2 * π * (a/2)² = πa²/8
Step 3: Find the Required Area of the Shaded Region
To find the area of the shaded region, we need to subtract the area of the semicircle ADB from the area of the quadrant ACB:
Required Area of Shaded Region = Area of Quadrant ACB - Area of Semicircle ADB
Required Area of Shaded Region = 1/4 * π * a² - πa²/8
Required Area of Shaded Region = 2πa²/8 - πa²/8
Required Area of Shaded Region = πa²/8
Final Answer:
Therefore, the area of the shaded region is given by πa²/8.