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The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, is
- a)0.64 A
- b)1.64 A
- c)2.64 A
- d)3.64 A
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The value of current, flowing through an inductor of inductance 1 H an...
Given,
Inductance, L = 1 H
Voltage, V = 200 V
Frequency, f = 50 Hz
Formula used:
The current flowing through an inductor is given by the formula:
I = V / XL
where XL = 2πfL is the inductive reactance of the inductor.
Calculation:
XL = 2πfL
= 2 x 3.14 x 50 x 1
= 314 Ω
I = V / XL
= 200 / 314
= 0.64 A
Therefore, the value of current flowing through the inductor is 0.64 A. Hence, option (a) is the correct answer.
Inductance, L = 1 H
Voltage, V = 200 V
Frequency, f = 50 Hz
Formula used:
The current flowing through an inductor is given by the formula:
I = V / XL
where XL = 2πfL is the inductive reactance of the inductor.
Calculation:
XL = 2πfL
= 2 x 3.14 x 50 x 1
= 314 Ω
I = V / XL
= 200 / 314
= 0.64 A
Therefore, the value of current flowing through the inductor is 0.64 A. Hence, option (a) is the correct answer.
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Community Answer
The value of current, flowing through an inductor of inductance 1 H an...
Given:
Inductance (L) = 1 H
Voltage (V) = 200 V
Frequency (f) = 50 Hz
Formula used:
The formula used to calculate the current flowing in an inductor is:
I = (V/Z)
Where,
I = Current flowing through the inductor
V = Voltage applied to the inductor
Z = Impedance of the inductor
Impedance of an inductor is given by:
Z = jωL
Where,
ω = 2πf
j = √(-1)
Calculation:
ω = 2πf = 2π x 50 = 100π
j = √(-1)
Z = jωL = j x 100π x 1 = 100jπ
I = (V/Z) = 200/100jπ
To simplify the expression, we can multiply and divide by j:
I = (200j)/(100jπ x j) = (2j)/(π)
Taking the magnitude of the complex number:
|I| = √(2²/π²) = 0.64 A
Therefore, the value of current flowing through the inductor is 0.64 A.
Answer: (a) 0.64 A
Inductance (L) = 1 H
Voltage (V) = 200 V
Frequency (f) = 50 Hz
Formula used:
The formula used to calculate the current flowing in an inductor is:
I = (V/Z)
Where,
I = Current flowing through the inductor
V = Voltage applied to the inductor
Z = Impedance of the inductor
Impedance of an inductor is given by:
Z = jωL
Where,
ω = 2πf
j = √(-1)
Calculation:
ω = 2πf = 2π x 50 = 100π
j = √(-1)
Z = jωL = j x 100π x 1 = 100jπ
I = (V/Z) = 200/100jπ
To simplify the expression, we can multiply and divide by j:
I = (200j)/(100jπ x j) = (2j)/(π)
Taking the magnitude of the complex number:
|I| = √(2²/π²) = 0.64 A
Therefore, the value of current flowing through the inductor is 0.64 A.
Answer: (a) 0.64 A
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The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer?.
The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer?.
Solutions for The value of current, flowing through an inductor of inductance 1 H and having negligible resistance when connected to an a.c. source of 200 V and 50 Hz, isa)0.64 Ab)1.64 Ac)2.64 Ad)3.64 ACorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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