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The ratio of available power from the dc component of a full-wave rectified sinusoid to the available power of the rectified sinusoid is?
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Ratio of Available Power from the DC Component of a Full-Wave Rectified Sinusoid to the Available Power of the Rectified Sinusoid

Introduction
When a sinusoidal signal is rectified, both the AC component and the DC component are obtained. The AC component represents the sinusoidal portion of the signal, while the DC component represents the average value of the rectified signal. In this explanation, we will discuss the ratio of available power from the DC component of a full-wave rectified sinusoid to the available power of the rectified sinusoid.

Full-Wave Rectification
Full-wave rectification is a process that converts an AC signal into a DC signal. It is achieved by using a diode bridge circuit that consists of four diodes. The diode bridge circuit allows the positive and negative halves of the AC signal to be rectified separately, resulting in a full-wave rectified output.

Power Calculation
To determine the ratio of available power from the DC component to the available power of the rectified sinusoid, we need to calculate the power in each component.

AC Component Power
The AC component of the rectified sinusoid represents the sinusoidal portion of the signal. The power in the AC component can be calculated using the formula:

P_AC = (V_AC^2) / R

where P_AC is the power in the AC component, V_AC is the peak voltage of the AC component, and R is the load resistance.

DC Component Power
The DC component of the rectified sinusoid represents the average value of the rectified signal. The power in the DC component can be calculated using the formula:

P_DC = (V_DC^2) / R

where P_DC is the power in the DC component, V_DC is the DC voltage level, and R is the load resistance.

Calculation of Ratios
To calculate the ratio of available power from the DC component to the available power of the rectified sinusoid, we divide the power in the DC component by the total power (sum of AC and DC component powers).

Ratio = P_DC / (P_AC + P_DC)

Simplifying the equation, we get:

Ratio = (V_DC^2) / [(V_AC^2) + (V_DC^2)]

Conclusion
In conclusion, the ratio of available power from the DC component of a full-wave rectified sinusoid to the available power of the rectified sinusoid is given by the equation: Ratio = (V_DC^2) / [(V_AC^2) + (V_DC^2)]. This ratio represents the proportion of power contributed by the DC component compared to the total power of the rectified signal.
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The ratio of available power from the dc component of a full-wave rectified sinusoid to the available power of the rectified sinusoid is?
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