A parallel RLC circuit resonates at 100 kHz. At frequency of 110khz. T...
Parallel RLC Circuit Impedance Calculation
Given Information:
- Resonant frequency, fr = 100 kHz
- Operating frequency, f = 110 kHz
Determination of Impedance:
The impedance of a parallel RLC circuit can be calculated using the following formula:
Z = R || [(1/jωC) - jωL]
Where,
- Z = Impedance in ohms
- R = Resistance in ohms
- C = Capacitance in farads
- L = Inductance in henries
- ω = Angular frequency in radians/second
Calculation:
Given that the circuit resonates at 100 kHz, the resonant angular frequency can be calculated as follows:
ωr = 2πfr = 2 × 3.14 × 100 × 103 = 628,318.53 rad/s
At resonance, the impedance of the circuit is purely resistive and is given by:
Zr = R
Let's assume that the resistance of the circuit is R = 100 Ω. Now, we can calculate the capacitance and inductance of the circuit using the resonant frequency as follows:
ωr = (1 / √LC)
L = 1 / (Cωr2)
C = 1 / (Lωr2)
Substituting the values, we get:
L = 5.08 mH, C = 31.84 nF
Now, we can calculate the impedance of the circuit at the operating frequency of 110 kHz using the same formula:
ω = 2πf = 2 × 3.14 × 110 × 103 = 689,405.49 rad/s
Z = R || [(1/jωC) - jωL]
Z = 100 || [(1/j(689,405.49)(31.84 × 10-9)) - j(689,405.49)(5.08 × 10-3)]
Z = 100 || (0.000013 - 3.51j)
Z = 100 || 3.51∠-89.19°
Z = 3.52 - j99.98 Ω
Conclusion:
Therefore, the impedance of the parallel RLC circuit at an operating frequency of 110 kHz is 3.52 - j99.98 Ω.