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A parallel RLC circuit resonates at 100 kHz. At frequency of 110khz. The circuit impedance will be?
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A parallel RLC circuit resonates at 100 kHz. At frequency of 110khz. T...
Parallel RLC Circuit Impedance Calculation


Given Information:


  • Resonant frequency, fr = 100 kHz

  • Operating frequency, f = 110 kHz



Determination of Impedance:

The impedance of a parallel RLC circuit can be calculated using the following formula:

Z = R || [(1/jωC) - jωL]

Where,


  • Z = Impedance in ohms

  • R = Resistance in ohms

  • C = Capacitance in farads

  • L = Inductance in henries

  • ω = Angular frequency in radians/second



Calculation:

Given that the circuit resonates at 100 kHz, the resonant angular frequency can be calculated as follows:

ωr = 2πfr = 2 × 3.14 × 100 × 103 = 628,318.53 rad/s

At resonance, the impedance of the circuit is purely resistive and is given by:

Zr = R

Let's assume that the resistance of the circuit is R = 100 Ω. Now, we can calculate the capacitance and inductance of the circuit using the resonant frequency as follows:

ωr = (1 / √LC)

L = 1 / (Cωr2)

C = 1 / (Lωr2)

Substituting the values, we get:

L = 5.08 mH, C = 31.84 nF

Now, we can calculate the impedance of the circuit at the operating frequency of 110 kHz using the same formula:

ω = 2πf = 2 × 3.14 × 110 × 103 = 689,405.49 rad/s

Z = R || [(1/jωC) - jωL]

Z = 100 || [(1/j(689,405.49)(31.84 × 10-9)) - j(689,405.49)(5.08 × 10-3)]

Z = 100 || (0.000013 - 3.51j)

Z = 100 || 3.51∠-89.19°

Z = 3.52 - j99.98 Ω


Conclusion:

Therefore, the impedance of the parallel RLC circuit at an operating frequency of 110 kHz is 3.52 - j99.98 Ω.
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A parallel RLC circuit resonates at 100 kHz. At frequency of 110khz. The circuit impedance will be?
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