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Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )?
Verified Answer
Ramu sells milk after adulterating X litres of pure milk with 0.75 lit...
Profit when tap water is added = 0.75C, Profit when mineral water is added = 0.75C - 4.5. Therefore, 0.75C - 4.5 = 0.85 (0.75C) which gives C = 53.33
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Ramu sells milk after adulterating X litres of pure milk with 0.75 lit...
Introduction:
Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water. However, if he uses 0.75 litres of mineral water instead, his profit would reduce by 15%. We need to determine the cost of pure milk per litre.
Given information:
- Ramu adulterates X litres of pure milk with 0.75 litres of tap water.
- If he uses 0.75 litres of mineral water instead, his profit reduces by 15%.
- The cost of mineral water is Rs. 12 per litre.
- Ramu always sells at cost price.
Approach:
To solve this problem, we can use the concept of cost price, selling price, and profit percentage.
1. Let's assume the cost price of pure milk per litre is C.
2. The cost price of 0.75 litres of tap water is 0, as it is obtained for free.
3. The cost price of 0.75 litres of mineral water is 0.75 * 12 = Rs. 9.
4. Ramu sells X litres of adulterated milk at cost price, so the selling price of X litres of milk is X * C.
5. If Ramu sells X litres of milk adulterated with mineral water, his profit reduces by 15%. Therefore, the new selling price would be 85% of X * C, which is 0.85 * X * C.
6. Ramu adulterates X litres of pure milk with 0.75 litres of tap water, so the quantity of adulterated milk becomes X + 0.75 litres.
7. Similarly, if he uses 0.75 litres of mineral water, the quantity of adulterated milk becomes X + 0.75 litres.
8. The ratio of pure milk to the adulterated milk should remain constant in both cases.
9. Therefore, we can write the equation: X / (X + 0.75) = (X + 0.75) / (X + 0.75).
10. Solving the equation, we can find the value of X.
Solution:
Let's calculate the value of X using the equation mentioned above.
(X / (X + 0.75)) = ((X + 0.75) / (X + 0.75))
X^2 + 0.75X = X + 0.75
X^2 - X - 0.75 = 0
Solving this quadratic equation, we get X = 1 or X = -0.75.
Since the quantity cannot be negative, we consider X = 1.
Now, using the selling price equation, we can find the cost of pure milk per litre.
Selling price of adulterated milk = X * C = 1 * C
Selling price of milk adulterated with mineral water = 0.85 * X * C = 0.85 * 1 * C = 0.85C
The difference between the two selling prices is the cost of 0.75 litres of mineral water.
0.85C - C = Rs. 9
0.15C = 9
C = 9 / 0.15
C = Rs.
Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water. However, if he uses 0.75 litres of mineral water instead, his profit would reduce by 15%. We need to determine the cost of pure milk per litre.
Given information:
- Ramu adulterates X litres of pure milk with 0.75 litres of tap water.
- If he uses 0.75 litres of mineral water instead, his profit reduces by 15%.
- The cost of mineral water is Rs. 12 per litre.
- Ramu always sells at cost price.
Approach:
To solve this problem, we can use the concept of cost price, selling price, and profit percentage.
1. Let's assume the cost price of pure milk per litre is C.
2. The cost price of 0.75 litres of tap water is 0, as it is obtained for free.
3. The cost price of 0.75 litres of mineral water is 0.75 * 12 = Rs. 9.
4. Ramu sells X litres of adulterated milk at cost price, so the selling price of X litres of milk is X * C.
5. If Ramu sells X litres of milk adulterated with mineral water, his profit reduces by 15%. Therefore, the new selling price would be 85% of X * C, which is 0.85 * X * C.
6. Ramu adulterates X litres of pure milk with 0.75 litres of tap water, so the quantity of adulterated milk becomes X + 0.75 litres.
7. Similarly, if he uses 0.75 litres of mineral water, the quantity of adulterated milk becomes X + 0.75 litres.
8. The ratio of pure milk to the adulterated milk should remain constant in both cases.
9. Therefore, we can write the equation: X / (X + 0.75) = (X + 0.75) / (X + 0.75).
10. Solving the equation, we can find the value of X.
Solution:
Let's calculate the value of X using the equation mentioned above.
(X / (X + 0.75)) = ((X + 0.75) / (X + 0.75))
X^2 + 0.75X = X + 0.75
X^2 - X - 0.75 = 0
Solving this quadratic equation, we get X = 1 or X = -0.75.
Since the quantity cannot be negative, we consider X = 1.
Now, using the selling price equation, we can find the cost of pure milk per litre.
Selling price of adulterated milk = X * C = 1 * C
Selling price of milk adulterated with mineral water = 0.85 * X * C = 0.85 * 1 * C = 0.85C
The difference between the two selling prices is the cost of 0.75 litres of mineral water.
0.85C - C = Rs. 9
0.15C = 9
C = 9 / 0.15
C = Rs.
Community Answer
Ramu sells milk after adulterating X litres of pure milk with 0.75 lit...
How did you get c=53.33 again solve the equation. and why did you substract 4.5 instead of 9. 0.75*12=9. explain it
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Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )?
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Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )?.
Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )?.
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Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )?, a detailed solution for Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? has been provided alongside types of Ramu sells milk after adulterating X litres of pure milk with 0.75 litres of tap water . If sold milk after adulterating x litres of pure milk with 0.75 litres of mineral water instead his profit would reduce by 15 % . What is the cost of pure milk per litre ? ( The cost of mineral water is Rs . 12 per litre and tap water comes for free . Ramu always sells at cost price . )? theory, EduRev gives you an
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