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If vectors abc satisfy the condition |a-c|=|b-c| then b-a.c-a b2=?
Most Upvoted Answer
If vectors abc satisfy the condition |a-c|=|b-c| then b-a.c-a b2=?
|b-a||c-a| = |b-c||c-a| = |a-c||c-a|
The magnitude of the left and right sides must be equal, so the product of the magnitudes on the left side must be equal to the product of the magnitudes on the right side.
Therefore, b2 - a2c2 = 0.
Community Answer
If vectors abc satisfy the condition |a-c|=|b-c| then b-a.c-a b2=?
Given Information:
We are given three vectors a, b, and c, and we are given the condition |a-c| = |b-c|.

Required:
We need to find the value of b^2 in terms of a and c.

Solution:

Step 1: Understanding the Condition
The condition |a-c| = |b-c| means that the magnitudes of the vectors a-c and b-c are equal. This implies that the vectors a-c and b-c have the same length.

Step 2: Expanding the Magnitudes
We can expand the magnitudes and rewrite the given condition as:
√((a-c) • (a-c)) = √((b-c) • (b-c))

Step 3: Simplifying the Equation
Squaring both sides of the equation, we get:
(a-c) • (a-c) = (b-c) • (b-c)

Expanding the dot products, we have:
a • a - 2(a • c) + c • c = b • b - 2(b • c) + c • c

The terms (a • c) and (c • c) are scalars, so they can be moved to the right side of the equation:
a • a - b • b = 2(b • c) - 2(a • c)

Rearranging the equation, we obtain:
b • b - a • a = 2(a • c - b • c)

Step 4: Finding b^2
Adding a • a to both sides of the equation, we get:
b • b = a • a + 2(a • c - b • c)

Step 5: Simplifying the Equation
We can rewrite the equation in terms of vector operations:
b • b = |a|^2 + 2(a • c - b • c)

Step 6: Rearranging the Equation
Subtracting 2(a • c) from both sides of the equation, we have:
b • b - 2(a • c) = |a|^2 - 2(b • c)

Step 7: Expanding the Dot Product
Expanding the dot products, we get:
b • (b - 2a) = |a|^2 - 2(b • c)

Step 8: Finding b^2
Dividing both sides of the equation by (b - 2a), we obtain:
b = (|a|^2 - 2(b • c)) / (b - 2a)

Therefore, the value of b^2 is:
b^2 = (|a|^2 - 2(b • c)) / (b - 2a)
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If vectors abc satisfy the condition |a-c|=|b-c| then b-a.c-a b2=?
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