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At high electric discharge hydrogen and oxygen combine to form _____________
  • a)
    acid
  • b)
    water
  • c)
    hydrogen peroxide
  • d)
    salt
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
At high electric discharge hydrogen and oxygen combine to form _______...
At 970 Kelvin, an electric discharge 2 moles of hydrogen molecule combines with one mole of Oxygen in order to form 2 moles of water. This has an enthalpy change of about 285.9 KJ/mol, the enthalpy change is negative for the above process.
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At high electric discharge hydrogen and oxygen combine to form _______...


Formation of Hydrogen Peroxide:
Hydrogen and oxygen combine to form hydrogen peroxide at high electric discharge. This process involves the following steps:

- Ionization of Hydrogen and Oxygen: When high electric discharge is applied, hydrogen and oxygen molecules become ionized, breaking into their constituent atoms.

- Formation of Free Radicals: The ionized atoms of hydrogen and oxygen then form free radicals, which are highly reactive species due to the presence of unpaired electrons.

- Combination of Hydrogen and Oxygen: The free radicals of hydrogen and oxygen combine to form hydrogen peroxide (H2O2) molecule.

- Chemical Equation: The overall chemical equation for the formation of hydrogen peroxide can be represented as: 2H + 2O -> 2H2O2

- Properties of Hydrogen Peroxide: Hydrogen peroxide is a colorless and odorless liquid that is slightly more viscous than water. It is a powerful oxidizing agent and has various uses in industries and laboratories.

In conclusion, at high electric discharge, hydrogen and oxygen react to form hydrogen peroxide through a series of ionization, radical formation, and combination reactions. This process is crucial for the production of hydrogen peroxide, an important chemical compound with diverse applications.
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At high electric discharge hydrogen and oxygen combine to form _____________a)acidb)waterc)hydrogen peroxided)saltCorrect answer is option 'C'. Can you explain this answer?
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