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Suppose we are sorting an array of eight integers using quicksort, and we have just finished the first partitioning with the array looking like this:
2  5  1  7  9  12  11  10 
Which statement is correct?
  • a)
    The pivot could be either the 7 or the 9.
  • b)
    The pivot could be the 7, but it is not the 9
  • c)
    The pivot is not the 7, but it could be the 9
  • d)
    Neither the 7 nor the 9 is the pivot.
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Suppose we are sorting an array of eight integers using quicksort, and...
7 and 9 both are at their correct positions (as in a sorted array). Also, all elements on left of 7 and 9 are smaller than 7 and 9 respectively and on right are greater than 7 and 9 respectively.
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Most Upvoted Answer
Suppose we are sorting an array of eight integers using quicksort, and...
Explanation:

In quicksort, the partitioning process involves selecting a pivot element from the array and rearranging the other elements such that all elements smaller than the pivot are moved to the left of it, and all elements greater than the pivot are moved to the right of it. After the partitioning process, the pivot element will be in its final sorted position.

In this scenario, the array after the first partitioning is: 2 5 1 7 9 12 11 10

To determine the correct statement, let's analyze the array and the partitioning process:

1. Pivot selection:
- The pivot element can be any element from the array. It is commonly chosen as the first, last, or middle element. In this case, let's assume the pivot is selected as the first element, which is 2.
- The partitioning process involves comparing each element with the pivot and rearranging them accordingly.

2. Partitioning process:
- Starting from the second element, we compare each element with the pivot (2) and rearrange them.
- After the partitioning process, the elements smaller than the pivot will be on the left side, and the elements greater than the pivot will be on the right side.
- The resulting array after partitioning: 1 2 5 7 9 12 11 10

Now let's analyze the given statements:

a) The pivot could be either the 7 or the 9.
- This statement is correct because during the partitioning process, the pivot element can be any element from the array. In this case, the pivot could have been either 7 or 9.

b) The pivot could be the 7, but it is not the 9.
- This statement is incorrect because the pivot could have been either 7 or 9.

c) The pivot is not the 7, but it could be the 9.
- This statement is incorrect because the pivot could have been either 7 or 9.

d) Neither the 7 nor the 9 is the pivot.
- This statement is incorrect because either 7 or 9 could have been the pivot.

Therefore, the correct statement is option 'a' - The pivot could be either the 7 or the 9.
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Suppose we are sorting an array of eight integers using quicksort, and we have just finished the first partitioning with the array looking like this:2 5 1 7 9 12 11 10Which statement is correct?a)The pivot could be either the 7 or the 9.b)The pivot could be the 7, but it is not the 9c)The pivot is not the 7, but it could be the 9d)Neither the 7 nor the 9 is the pivot.Correct answer is option 'A'. Can you explain this answer?
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