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In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.
if T(Pr) < T(Ph)
if T(Pr) < T(Ph)
then kill Pr
else wait
Which one of the following is TRUE?
Which one of the following is TRUE?
- a)The scheme is deadlock-free, but not starvation-free
- b)The scheme is not deadlock-free, but starvation-free
- c)The scheme is neither deadlock-free nor starvation-free
- d)The scheme is both deadlock-free and starvation-free
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In a certain operating system, deadlock prevention is attempted using ...
- This scheme is making sure that the timestamp of requesting process is always lesser than holding process
- The process is restarted with same timestamp if killed and that timestamp can NOT be greater than the existing time stamp
From 1 and 2,it is clear that any new process coming having LESSER timestamp will be KILLED.So,NO DEADLOCK possible However, a new process will lower timestamp may have to wait infinitely because of its LOWER timestamp(as killed process will also have same timestamp ,as it was killed earlier).STARVATION IS Definitely POSSIBLE So Answer is A
Most Upvoted Answer
In a certain operating system, deadlock prevention is attempted using ...
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If T(Pr) > T(Ph), then Ph is preempted and Pr is allowed to proceed.
This deadlock prevention scheme ensures that a process with a higher timestamp is given priority over a process with a lower timestamp. This helps to prevent deadlocks by ensuring that processes with higher timestamps are not indefinitely blocked by processes with lower timestamps.
By assigning each process a unique timestamp and restarting them with the same timestamp if killed, this scheme ensures that processes retain their priority even after being restarted. This helps to maintain the order of execution and prevent deadlocks.
However, it is important to note that this scheme does not guarantee complete deadlock prevention. It only helps in preventing deadlocks caused by resource allocation. Other types of deadlocks, such as circular wait, cannot be prevented solely by this scheme. Therefore, additional deadlock prevention mechanisms may still be required in the operating system.
If T(Pr) > T(Ph), then Ph is preempted and Pr is allowed to proceed.
This deadlock prevention scheme ensures that a process with a higher timestamp is given priority over a process with a lower timestamp. This helps to prevent deadlocks by ensuring that processes with higher timestamps are not indefinitely blocked by processes with lower timestamps.
By assigning each process a unique timestamp and restarting them with the same timestamp if killed, this scheme ensures that processes retain their priority even after being restarted. This helps to maintain the order of execution and prevent deadlocks.
However, it is important to note that this scheme does not guarantee complete deadlock prevention. It only helps in preventing deadlocks caused by resource allocation. Other types of deadlocks, such as circular wait, cannot be prevented solely by this scheme. Therefore, additional deadlock prevention mechanisms may still be required in the operating system.
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In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer?
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In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer?.
In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer?.
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In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a certain operating system, deadlock prevention is attempted using the following scheme. Each process is assigned a unique timestamp, and is restarted with the same timestamp if killed. Let Ph be the process holding a resource R, Pr be a process requesting for the same resource R, and T(Ph) and T(Pr) be their timestamps respectively. The decision to wait or preempt one of the processes is based on the following algorithm.if T(Pr) < T(Ph)then kill Prelse waitWhich one of the following is TRUE?a)The scheme is deadlock-free, but not starvation-freeb)The scheme is not deadlock-free, but starvation-freec)The scheme is neither deadlock-free nor starvation-freed)The scheme is both deadlock-free and starvation-freeCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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