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Four jobs to be executed on a single processor system arrive at time 0 in the order A, B, C, D . Their burst CPU time requirements are 4, 1, 8, 1 time units respectively. The completion time of A under round robin scheduling with time slice of one time unit is
  • a)
    10
  • b)
    4
  • c)
    8
  • d)
    9
Correct answer is option 'D'. Can you explain this answer?
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Four jobs to be executed on a single processor system arrive at time 0...
The order of execution of the processes with the arrival time of each process = 0, using round robin algorithm with time quanta = 1 A B C D A C A C A, i.e, after 8 context switches, A finally completes it execution So, the correct option is (D).
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Four jobs to be executed on a single processor system arrive at time 0...
Explanation:

  • The given problem can be solved using round robin scheduling algorithm where CPU executes each process for a time slice of 1 unit and moves to the next process in the queue.

  • The total time required to complete all the jobs can be calculated as follows:


Total time = (4+1+8+1) = 14 units


  • The process A arrives first in the queue and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process B arrives next and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process C arrives next and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process D arrives next and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process A arrives at the head of the queue again and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process C arrives at the head of the queue and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process D arrives at the head of the queue and is executed for 1 unit of time. Then it is moved to the end of the queue as it has not completed its execution.

  • The process A arrives at the head of the queue again and is executed for 1 unit of time. This completes the execution of process A.


Hence, the completion time of process A is 1+4=5 units.


  • The remaining processes B, C and D are executed in a similar manner.

  • The completion time of process B is 6 units.

  • The completion time of process C is 11 units.

  • The completion time of process D is 14 units.


Therefore, the completion time of A under round robin scheduling with time slice of one time unit is 5 units.

Hence, the correct answer is option 'D'.
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Three processes A, B and C each execute a loop of 100 iterations. In each iteration of the loop, a process performs a single computation that requires tc CPU milliseconds and then initiates a single I/O operation that lasts for tio milliseconds. It is assumed that the computer where the processes execute has sufficient number of I/O devices and the OS of the computer assigns different I/O devices to each process. Also, the scheduling overhead of the OS is negligible. The processes have the following characteristics:Process id tc tioA 100 ms 500 msB 350 ms 500 msC 200 ms 500 msQ.The processes A, B, and C are started at times 0, 5 and 10 milliseconds respectively, in a pure time sharing system (round robin scheduling) that uses a time slice of 50 milliseconds. The time in milliseconds at which process C would complete its first I/O operation is ___________.

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Four jobs to be executed on a single processor system arrive at time 0 in the order A, B, C, D . Their burst CPU time requirements are 4, 1, 8, 1 time units respectively. The completion time of A under round robin scheduling with time slice of one time unit isa)10b)4c)8d)9Correct answer is option 'D'. Can you explain this answer?
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