Spin Only Magnetic Moment in FeF6 3-

The spin only magnetic moment refers to the magnetic moment that arises due to the spin of unpaired electrons in a compound. It is calculated using the formula:

μs = √n(n+2) BM

Where μs is the spin only magnetic moment, n is the number of unpaired electrons, and BM is the Bohr magneton (9.27 x 10^-24 J/T).

To determine the spin only magnetic moment in FeF6 3-, we need to first determine the number of unpaired electrons in the compound.

Unpaired Electrons in FeF6 3-

In FeF6 3-, iron (Fe) has a +3 oxidation state. The electronic configuration of Fe in its +3 oxidation state is [Ar] 3d5.

To determine the number of unpaired electrons, we need to consider the Hund's rule. According to Hund's rule, electrons occupy separate orbitals in the same subshell before pairing up.

In the case of FeF6 3-, the 3d subshell has five orbitals (3dxy, 3dxz, 3dyz, 3dx2-y2, and 3dz2). Since there are five unpaired electrons in the 3d subshell of Fe, the number of unpaired electrons in FeF6 3- is 5.

Calculating the Spin Only Magnetic Moment

Using the formula:

μs = √n(n+2) BM

Substituting the value of n (5) into the formula, we get:

μs = √5(5+2) BM
= √5(7) BM
= √35 BM

Therefore, the spin only magnetic moment in FeF6 3- is √35 BM.

Spin Only Magnetic Moment in Co(CN)5H2O3-

To determine the spin only magnetic moment in Co(CN)5H2O3-, we need to first determine the number of unpaired electrons in the complex.

Unpaired Electrons in Co(CN)5H2O3-

In Co(CN)5H2O3-, cobalt (Co) has a +3 oxidation state. The electronic configuration of Co in its +3 oxidation state is [Ar] 3d6.

To determine the number of unpaired electrons, we need to consider the Hund's rule. In the case of Co(CN)5H2O3-, the 3d subshell has six orbitals. However, the presence of the ligands (CN and H2O) will cause the splitting of the d orbitals into two sets: t2g (lower energy) and eg (higher energy).

Based on the ligand field theory, the CN and H2O ligands will cause the t2g orbitals to be filled before the eg orbitals. Therefore, three of the six 3d orbitals in Co(CN)5H2O3- will be occupied by electrons, resulting in three unpaired electrons.

Calculating the Spin Only Magnetic Moment

Using the formula:

μs = √n(n+2) BM

Substituting the value of n (3)