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A computer has six tape drives, with n processes competing for them. Each process may need two drives. What is the maximum value of n for the system to be deadlock free?
  • a)
    6
  • b)
    5
  • c)
    4
  • d)
    3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A computer has six tape drives, with n processes competing for them. E...
Given tape drive = 6 and each process may need 2 drive. When we give 1 drive to 1 process then total process will be 6 but in this case there will definitely deadlock occur because every process contain 1 drive and waiting for another drive which is hold by other process therefore when we reduce 1 process then system to be deadlock free. Hence maximum value of n = 6 - 1 = 5. Option (B) is correct.
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Community Answer
A computer has six tape drives, with n processes competing for them. E...
To determine the maximum value of n for the system to be deadlock free, we need to consider the number of available tape drives and the number of processes competing for them.

Given:
- There are six tape drives available.
- Each process may need two drives.

To avoid deadlock, we need to ensure that there are always enough tape drives available for each process to complete its task. This means that no process should be left waiting indefinitely for the required number of tape drives.

Let's consider different scenarios based on the number of processes:

1. n = 1:
- In this case, only one process is competing for the tape drives.
- As each process needs two drives, it will create a deadlock because there are not enough drives available.
- Therefore, n = 1 is not a valid option.

2. n = 2:
- With two processes competing for the tape drives, each needing two drives, the total number of drives required is 4 (2 * 2 = 4).
- Since there are six drives available, this scenario is deadlock free.
- Therefore, n = 2 is a valid option.

3. n = 3:
- With three processes competing for the tape drives, each needing two drives, the total number of drives required is 6 (3 * 2 = 6).
- In this scenario, all the available drives are required, leaving no drives for any additional processes.
- Therefore, n = 3 is not a valid option.

4. n = 4:
- With four processes competing for the tape drives, each needing two drives, the total number of drives required is 8 (4 * 2 = 8).
- Since there are only six drives available, this scenario will create a deadlock because there are not enough drives for all the processes.
- Therefore, n = 4 is not a valid option.

5. n = 5:
- With five processes competing for the tape drives, each needing two drives, the total number of drives required is 10 (5 * 2 = 10).
- Since there are only six drives available, this scenario will create a deadlock because there are not enough drives for all the processes.
- Therefore, n = 5 is not a valid option.

Based on the analysis above, the maximum value of n for the system to be deadlock free is n = 2, making option B the correct answer.
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A computer has six tape drives, with n processes competing for them. Each process may need two drives. What is the maximum value of n for the system to be deadlock free?a)6b)5c)4d)3Correct answer is option 'B'. Can you explain this answer?
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