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An operating system contains 3 user processes each requiring 2 units of resource R. The minimum number of units of R such that no deadlocks will ever arise is
  • a)
    3
  • b)
    5
  • c)
    4
  • d)
    6
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An operating system contains 3 user processes each requiring 2 units o...
Total process = 3 and each require 2 units of resource. If we give 1 resource to 1 process then total resource = 1 + 1 + 1 = 3 but in this case deadlock will definitely occur because each process hold 1 unit resource and waiting for another resource so if we increase 1 more resource (3+1=4) then deadlocks will ever arise (i.e., when process 1 complete their execution then it free 2 resource and this 2 resource will used by another process.). Option (B) is correct.
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Community Answer
An operating system contains 3 user processes each requiring 2 units o...
Explanation:
In order to avoid deadlocks, we need to make sure that each process can acquire the required resources without any resource being held indefinitely by another process.

Understanding the Problem:
- There are 3 user processes.
- Each process requires 2 units of resource R.
- We need to find the minimum number of units of R such that no deadlocks will ever arise.

Resource Allocation:
- If we have only 2 units of resource R, then it is possible for each process to acquire 1 unit of R, but the remaining unit will be unavailable.
- This can lead to a deadlock situation where each process is waiting for the additional unit of R that is held by another process.
- To avoid deadlocks, we need to ensure that all processes can acquire the required 2 units of R simultaneously.

Minimum Number of Units:
- If we allocate 3 units of resource R, each process can acquire the required 2 units simultaneously without any deadlock.
- This is because there are enough units of R available for all processes to proceed without waiting for each other.
- Therefore, the minimum number of units of R required to avoid deadlocks is 3.

Answer:
The correct answer is option B) 5.

Additional Explanation:
- In this scenario, each process requires 2 units of resource R.
- If we allocate only 4 units of R, it is possible for two processes to acquire 2 units each, but the third process will be left waiting.
- This can lead to a deadlock situation where the third process is waiting for the additional 2 units of R that are held by the other two processes.
- Therefore, we need a minimum of 5 units of R to ensure that all processes can acquire the required resources simultaneously and avoid deadlocks.
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An operating system contains 3 user processes each requiring 2 units of resource R. The minimum number of units of R such that no deadlocks will ever arise isa)3b)5c)4d)6Correct answer is option 'B'. Can you explain this answer?
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