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What is the probability that 3 children selected at random would have different birthdays?
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What is the probability that 3 children selected at random would have ...
Probability of three children having different birthdays


Explanation


Let's assume there are 365 days in a year (not accounting for leap years) and each day is equally likely to be someone's birthday. The probability of two people having the same birthday is:


P(2 people have the same birthday) = 1/365 (since there are 365 possible birthdays)


Using the complement rule, we can find the probability of three people having different birthdays:


P(3 people have different birthdays) = 1 - P(2 people have the same birthday)


Now, let's break down the calculation:



  • The probability that the second person doesn't have the same birthday as the first is 364/365.

  • The probability that the third person doesn't have the same birthday as either the first or second is 363/365.



So the probability of three people having different birthdays is:


P(3 people have different birthdays) = 1 - (1/365) * (364/365) * (363/365) = 0.9918


Conclusion


Therefore, the probability that 3 children selected at random would have different birthdays is 0.9918 or approximately 99.18%. This means that it is highly likely that three children selected at random will have different birthdays.
Community Answer
What is the probability that 3 children selected at random would have ...
362/365 in normal year
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What is the probability that 3 children selected at random would have different birthdays?
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