What is the probability that 3 children selected at random would have ...
Probability of three children having different birthdays
Explanation
Let's assume there are 365 days in a year (not accounting for leap years) and each day is equally likely to be someone's birthday. The probability of two people having the same birthday is:
P(2 people have the same birthday) = 1/365 (since there are 365 possible birthdays)
Using the complement rule, we can find the probability of three people having different birthdays:
P(3 people have different birthdays) = 1 - P(2 people have the same birthday)
Now, let's break down the calculation:
- The probability that the second person doesn't have the same birthday as the first is 364/365.
- The probability that the third person doesn't have the same birthday as either the first or second is 363/365.
So the probability of three people having different birthdays is:
P(3 people have different birthdays) = 1 - (1/365) * (364/365) * (363/365) = 0.9918
Conclusion
Therefore, the probability that 3 children selected at random would have different birthdays is 0.9918 or approximately 99.18%. This means that it is highly likely that three children selected at random will have different birthdays.