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The algebraic sum of deviations of 8,1,6 from AM 5 is?
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The algebraic sum of deviations of 8,1,6 from AM 5 is?
Calculation of Deviations and Algebraic Sum:
- First, calculate the mean (AM) of the given numbers: 8, 1, 6
Mean = (8 + 1 + 6) / 3 = 15 / 3 = 5
- Calculate the deviations of each number from the mean:
Deviation of 8 = 8 - 5 = 3
Deviation of 1 = 1 - 5 = -4
Deviation of 6 = 6 - 5 = 1
- Now, find the algebraic sum of these deviations:
Algebraic sum = 3 + (-4) + 1 = 0

Explanation:
- The algebraic sum of deviations from the mean is always zero. This is because some deviations are positive (above the mean) and some are negative (below the mean), and they cancel each other out when added together.
- In this case, the deviations from the mean for the numbers 8, 1, and 6 are 3, -4, and 1 respectively. When we add these deviations together, we get a sum of zero.
- This property of the algebraic sum of deviations being zero is a fundamental concept in statistics and is used in various calculations and analyses.
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