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A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.?
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A spherical shell of 800 mm diameter is subjected to an internal press...
Problem: Determine the minimum thickness of a spherical shell of 800 mm diameter subjected to an internal pressure of 1.5 MPa, if the tensile stress is not to exceed 40 52 pm.
Solution:
To determine the minimum thickness of the spherical shell, we need to use the formula for hoop stress and solve for thickness.
Hoop Stress Formula:
Hoop stress is the tangential stress that is induced in the walls of the spherical shell due to the internal pressure. The hoop stress is given by the formula:
σ_h = p x d / (2 x t)
where,
σ_h = hoop stress
p = internal pressure
d = diameter of the spherical shell
t = thickness of the spherical shell
Calculation:
Given that,
Diameter of the spherical shell (d) = 800 mm
Internal pressure (p) = 1.5 MPa
Maximum allowable tensile stress (σ_h) = 40 52 pm
Substituting the given values in the hoop stress formula, we get:
σ_h = p x d / (2 x t)
40 52 pm = 1.5 MPa x 800 mm / (2 x t)
Solving for t, we get:
t = p x d / (2 x σ_h)
t = 1.5 MPa x 800 mm / (2 x 40 52 pm)
t = 0.00015 m
Therefore, the minimum thickness of the spherical shell should be 0.15 mm.
Conclusion:
The minimum thickness of the spherical shell of 800 mm diameter subjected to an internal pressure of 1.5 MPa, if the tensile stress is not to exceed 40 52 pm is 0.15 mm.
Solution:
To determine the minimum thickness of the spherical shell, we need to use the formula for hoop stress and solve for thickness.
Hoop Stress Formula:
Hoop stress is the tangential stress that is induced in the walls of the spherical shell due to the internal pressure. The hoop stress is given by the formula:
σ_h = p x d / (2 x t)
where,
σ_h = hoop stress
p = internal pressure
d = diameter of the spherical shell
t = thickness of the spherical shell
Calculation:
Given that,
Diameter of the spherical shell (d) = 800 mm
Internal pressure (p) = 1.5 MPa
Maximum allowable tensile stress (σ_h) = 40 52 pm
Substituting the given values in the hoop stress formula, we get:
σ_h = p x d / (2 x t)
40 52 pm = 1.5 MPa x 800 mm / (2 x t)
Solving for t, we get:
t = p x d / (2 x σ_h)
t = 1.5 MPa x 800 mm / (2 x 40 52 pm)
t = 0.00015 m
Therefore, the minimum thickness of the spherical shell should be 0.15 mm.
Conclusion:
The minimum thickness of the spherical shell of 800 mm diameter subjected to an internal pressure of 1.5 MPa, if the tensile stress is not to exceed 40 52 pm is 0.15 mm.
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A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.?
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A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.?.
A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spherical shell of 800 mm diameter is subjected to an internal pressure of 1.5 MPa. What should be the minimum thickness of the shell, if the tensile stress is not to exceed 40 52 pm (Ans.?.
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