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Abag contains Rs.216,in the form of one rupee.50- paise 25 paise coins in the ratio2:3:4.The number of 50 paise coin is?
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Abag contains Rs.216,in the form of one rupee.50- paise 25 paise coins...
Given:

  • Total amount in the bag = Rs. 216

  • Coins are in the ratio 2:3:4



To find: Number of 50 paise coins

Solution:
Let the number of one rupee coins be 2x
Let the number of 50 paise coins be 3x
Let the number of 25 paise coins be 4x

The total amount in the bag is the sum of the value of all the coins.
Therefore,

Total amount = (value of one rupee coins) + (value of 50 paise coins) + (value of 25 paise coins)

216 = 2x + (0.5 x 3x) + (0.25 x 4x)

216 = 2x + 1.5x + x

216 = 4.5x

x = 48

Therefore, the number of 50 paise coins = 3x = 3 x 48 = 144

Answer: The number of 50 paise coins is 144.
Community Answer
Abag contains Rs.216,in the form of one rupee.50- paise 25 paise coins...
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Abag contains Rs.216,in the form of one rupee.50- paise 25 paise coins in the ratio2:3:4.The number of 50 paise coin is?
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