Draw the graph of the polynomial x^2-3x-10 Read of the zeros of the po...
Graph of the polynomial x^2-3x-10
To draw the graph of the polynomial x^2-3x-10, we need to follow the steps given below:
Step 1: Find the x-intercepts or zeros of the polynomial
To find the zeros of the polynomial, we need to set the polynomial equal to zero and solve for x.
x^2-3x-10 = 0
To solve this quadratic equation, we can factor it as:
(x-5)(x+2) = 0
This gives us two solutions: x=5 and x=-2.
So, the x-intercepts or zeros of the polynomial are (5,0) and (-2,0).
Step 2: Find the vertex of the parabola
The vertex of the parabola is the point where the curve changes direction. The x-coordinate of the vertex can be found using the formula:
x = -b/2a
where a=1, b=-3, and c=-10 (from the original polynomial).
So, x = -(-3)/(2*1) = 3/2.
The y-coordinate of the vertex can be found by plugging in x=3/2 into the original polynomial:
y = (3/2)^2 - 3(3/2) - 10 = -29/4
So, the vertex of the parabola is (3/2, -29/4).
Step 3: Plot the points on a coordinate plane and draw the parabola
Using the x-intercepts and vertex, we can plot the points on a coordinate plane and draw the parabola. The axis of symmetry is a vertical line that passes through the vertex.
The graph of the polynomial x^2-3x-10 is shown below:
The axis of symmetry is the vertical line x=3/2.
Therefore, the zeros of the polynomial are (5,0) and (-2,0), and the axis of symmetry is x=3/2.