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Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 20 = 0 is
  • a)
    1 unit
  • b)
    5/3 units
  • c)
    10/3 units
  • d)
    3 units
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 2...
3x + 4y - 15 = 0
Or 9x + 12y -45 = 0………………..(1)
And 9x + 12y - 20 = 0………………(2)
The distance between two parallel lines
ax + by +c1 = 0 and ax + by +c2 = 0 is
=
= 25/15 = 5/3 units
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Most Upvoted Answer
Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 2...
To find the distance between two parallel lines, we can use the formula:

Distance = |c1 - c2| / √(A² + B²)

where A and B are the coefficients of x and y in the equations of the lines, and c1 and c2 are the constants in the equations.

Given parallel lines:

3x + 4y - 15 = 0 ...(1)
9x + 12y - 20 = 0 ...(2)

Comparing equations (1) and (2), we can see that both have the same slope (3/4) and the same distance from the origin (15/√(3²+4²) = 15/5 = 3).

Therefore, the lines are parallel.

Using the formula, we can calculate the distance between the lines:

A = 3, B = 4, c1 = -15, c2 = -20

Distance = |-15 - (-20)| / √(3² + 4²)
= 5 / √(9 + 16)
= 5 / √25
= 5 / 5
= 1

Therefore, the distance between the given parallel lines is 1 unit.

Hence, the correct answer is option A) 1 unit.
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Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 20 = 0 isa)1 unitb)5/3 unitsc)10/3 unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer?
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