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Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 20 = 0 is
  • a)
    1 unit
  • b)
    5/3 units
  • c)
    10/3 units
  • d)
    3 units
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 2...
3x + 4y - 15 = 0
Or 9x + 12y - 45 = 0 --------- (1)
and 9x + 12y - 20 = 0 --------- (2)
The distance between two parallel lines
ax + by + c1 = 0 and ax + by + C2 = 0 is
= 25/15 = 5/3 units
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Most Upvoted Answer
Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 2...
Distance between parallel lines

Given equations:
1. 3x + 4y - 15 = 0
2. 9x + 12y - 20 = 0

Finding the distance:
To find the distance between two parallel lines, we use the formula:
Distance = |c2 - c1| / √(a^2 + b^2)
Where c1 and c2 are constants in the equations ax + by + c = 0.

Calculations:
1. For the first equation (3x + 4y - 15 = 0):
a1 = 3, b1 = 4, c1 = -15
2. For the second equation (9x + 12y - 20 = 0):
a2 = 9, b2 = 12, c2 = -20
Plugging the values into the formula:
Distance = |(-20) - (-15)| / √(9^2 + 12^2)
Distance = |5| / √(81 + 144)
Distance = 5 / √225
Distance = 5 / 15
Distance = 1/3 units
Therefore, the distance between the parallel lines is 5/3 units. Option B is the correct answer.
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Distance between the parallel lines 3x + 4y – 15 = 0 and 9x + 12y – 20 = 0 isa)1 unitb)5/3 unitsc)10/3 unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer?
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