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1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ml of CCI4 . If the equilibrium amount of A in the aqueous layer is 0.5, the partition co-efficient of A between CCl4 layer and water layer is (a) 43 (c) 60 (b) 40 (d) 80?
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1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ...
Calculation of Partition Coefficient of A between CCl4 and Water

Given: Amount of solute A = 2.0 g
Volume of water = 100.0 ml
Volume of CCl4 = 5.0 ml
Equilibrium amount of A in the aqueous layer = 0.5

Step 1: Calculation of concentration of A in water layer
Concentration of A in water layer = Equilibrium amount of A in the aqueous layer/Volume of water
= 0.5/100.0
= 0.005 mol/L

Step 2: Calculation of concentration of A in CCl4 layer
As the amount of A in CCl4 layer is not given, let us assume it to be x grams.
Then, concentration of A in CCl4 layer = x/5.0
Molar mass of A = M
Molar concentration of A in CCl4 layer = (x/M)/5.0
As the system has reached equilibrium, the total amount of A in both layers is constant.
Therefore, the total amount of A in both layers can be expressed as:
2.0 g = x + (0.005*M*100.0)
x = 2.0 - 0.5M
Substituting this value in the expression for molar concentration of A in CCl4 layer, we get:
Molar concentration of A in CCl4 layer = (0.1 - 0.025M)/M

Step 3: Calculation of Partition Coefficient of A between CCl4 and Water
Partition Coefficient (P) is defined as the ratio of concentration of A in CCl4 layer to that in water layer at equilibrium.
P = Molar concentration of A in CCl4 layer/Concentration of A in water layer
P = [(0.1 - 0.025M)/M]/0.005
P = (20 - 5M)/M

Step 4: Substituting the value of Equilibrium amount of A in the aqueous layer
Given that Equilibrium amount of A in the aqueous layer = 0.5
Concentration of A in water layer = Equilibrium amount of A in the aqueous layer/Volume of water
= 0.5/100.0
= 0.005 mol/L
Substituting this value in the expression for P, we get:
P = (20 - 5M)/M = 40

Therefore, the partition coefficient of A between CCl4 layer and water layer is 40.
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1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ml of CCI4 . If the equilibrium amount of A in the aqueous layer is 0.5, the partition co-efficient of A between CCl4 layer and water layer is (a) 43 (c) 60 (b) 40 (d) 80?
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1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ml of CCI4 . If the equilibrium amount of A in the aqueous layer is 0.5, the partition co-efficient of A between CCl4 layer and water layer is (a) 43 (c) 60 (b) 40 (d) 80? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ml of CCI4 . If the equilibrium amount of A in the aqueous layer is 0.5, the partition co-efficient of A between CCl4 layer and water layer is (a) 43 (c) 60 (b) 40 (d) 80? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1, 2.0 g of solute A is distributed between 100.0 ml of water and 5.0 ml of CCI4 . If the equilibrium amount of A in the aqueous layer is 0.5, the partition co-efficient of A between CCl4 layer and water layer is (a) 43 (c) 60 (b) 40 (d) 80?.
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