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Two coils of inductances 4 H and 6 H are connected in parallel. If their mutual inductance is 3H, calculate the equivalent inductance of the combination mutual inductance opposes the self-inductance.
  • a)
    0.9375 H
  • b)
    1.9375 H
  • c)
    0.5643 H
  • d)
    1.6753 H
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two coils of inductances 4 H and 6 H are connected in parallel. If th...
Given
L1 = 4H L2 = 6H M = 3H
Mutual inductance opposes the .
Important:
Mutual inductance assists the self-inductance
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Most Upvoted Answer
Two coils of inductances 4 H and 6 H are connected in parallel. If th...
Given:
Inductance of coil 1, L1 = 4 H
Inductance of coil 2, L2 = 6 H
Mutual inductance, M = 3 H

To find: Equivalent inductance of the combination

Solution:
When two inductors are connected in parallel, their equivalent inductance is given by:

1/L = 1/L1 + 1/L2 + 2M/(L1L2)

Substituting the given values, we get:

1/L = 1/4 + 1/6 + 2(3)/(4*6)
1/L = 12/24 + 8/24 + 6/24
1/L = 26/24
L = 24/26
L = 0.9375 H

Therefore, the equivalent inductance of the combination is 0.9375 H.

Hence, option A is the correct answer.
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Two coils of inductances 4 H and 6 H are connected in parallel. If their mutual inductance is 3H, calculate the equivalent inductance of the combination mutual inductance opposes the self-inductance.a)0.9375 Hb)1.9375 Hc)0.5643 Hd)1.6753 HCorrect answer is option 'A'. Can you explain this answer?
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