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200 V DC motor draws an armature current of 25 A. Its armature resistance is 0.8 ohm. The induced emf in the motor will be:
- a)240 V
- b)220 V
- c)180 V
- d)200 V
Correct answer is option 'C'. Can you explain this answer?
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200 V DC motor draws an armature current of 25 A. Its armature resist...
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In a DC generator, generated emf is given by
Eg = Vt + IaRa
In a DC motor, back emf is given by
Eb = V – IaRa
Where, Ia is armature current
Ra is armature resistance
Calculation:
Armature current (Ia) = 25 A
Armature resistance (Ra) = 0.8 ohm
Voltage (V) = 200 V
Ea = V – IaRa = 200 – 25(0.8) = 180 V
Most Upvoted Answer
200 V DC motor draws an armature current of 25 A. Its armature resist...
Given data:
- Armature current (Ia) = 25 A
- Armature resistance (Ra) = 0.8 ohm
- DC motor
To find:
- Induced emf in the motor
The induced emf in a DC motor can be calculated using the formula:
E = V - Ia * Ra
Where:
- E is the induced emf
- V is the applied voltage
- Ia is the armature current
- Ra is the armature resistance
Substituting the given values into the formula:
E = V - 25 * 0.8
Now let's solve the equation:
1. Rearrange the equation:
E + 20 = V
2. Substitute the value of V (200V) into the equation:
E + 20 = 200
3. Solve for E:
E = 200 - 20
E = 180 V
Hence, the induced emf in the motor is 180 V.
Therefore, the correct answer is option 'C' (180 V).
- Armature current (Ia) = 25 A
- Armature resistance (Ra) = 0.8 ohm
- DC motor
To find:
- Induced emf in the motor
The induced emf in a DC motor can be calculated using the formula:
E = V - Ia * Ra
Where:
- E is the induced emf
- V is the applied voltage
- Ia is the armature current
- Ra is the armature resistance
Substituting the given values into the formula:
E = V - 25 * 0.8
Now let's solve the equation:
1. Rearrange the equation:
E + 20 = V
2. Substitute the value of V (200V) into the equation:
E + 20 = 200
3. Solve for E:
E = 200 - 20
E = 180 V
Hence, the induced emf in the motor is 180 V.
Therefore, the correct answer is option 'C' (180 V).
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200 V DC motor draws an armature current of 25 A. Its armature resistance is 0.8 ohm. The induced emf in the motor will be:a)240 Vb)220 Vc)180 Vd)200 VCorrect answer is option 'C'. Can you explain this answer?
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