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Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....
- a)2 : 3
- b)3 : 1
- c)3 : 2
- d)1:3
Correct answer is option 'B'. Can you explain this answer?
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Two generators A and B have 6 -poles each. Generator A has wave wound ...
Ratio of induced e.m.f. in generator A and B
Given,
Number of poles in generator A and B = 6
Armature winding in generator A = Wave wound
Armature winding in generator B = Lap wound
Formula to calculate induced e.m.f. in a generator is given as:
E = 2.22 * N * Ø * Z * P / 60A
where,
E = Induced e.m.f.
N = Speed of the armature in revolutions per minute (rpm)
Ø = Flux per pole in webers
Z = Total number of conductors
P = Number of poles
A = Number of parallel paths
Let's assume that the flux per pole and the number of parallel paths are the same for both generators A and B.
Ratio of induced e.m.f. in generator A and B can be calculated as:
Ea / Eb = (N * Za * Pa) / (N * Zb * Pb)
Ea / Eb = (Za * Pa) / (Zb * Pb)
Now, let's calculate the values of Za, Pa, Zb, and Pb for both generators A and B.
Generator A:
Za = 2 * 6 = 12 (since wave winding has two paths)
Pa = 1 (since wave winding has only one coil per pole)
Generator B:
Zb = 6 (since lap winding has one path)
Pb = 3 (since lap winding has three coils per pole)
Substituting the values of Za, Pa, Zb, and Pb in the above formula, we get:
Ea / Eb = (12 * 1) / (6 * 3) = 2/1
Therefore, the ratio of induced e.m.f. in generator A and B is 3:1.
Given,
Number of poles in generator A and B = 6
Armature winding in generator A = Wave wound
Armature winding in generator B = Lap wound
Formula to calculate induced e.m.f. in a generator is given as:
E = 2.22 * N * Ø * Z * P / 60A
where,
E = Induced e.m.f.
N = Speed of the armature in revolutions per minute (rpm)
Ø = Flux per pole in webers
Z = Total number of conductors
P = Number of poles
A = Number of parallel paths
Let's assume that the flux per pole and the number of parallel paths are the same for both generators A and B.
Ratio of induced e.m.f. in generator A and B can be calculated as:
Ea / Eb = (N * Za * Pa) / (N * Zb * Pb)
Ea / Eb = (Za * Pa) / (Zb * Pb)
Now, let's calculate the values of Za, Pa, Zb, and Pb for both generators A and B.
Generator A:
Za = 2 * 6 = 12 (since wave winding has two paths)
Pa = 1 (since wave winding has only one coil per pole)
Generator B:
Zb = 6 (since lap winding has one path)
Pb = 3 (since lap winding has three coils per pole)
Substituting the values of Za, Pa, Zb, and Pb in the above formula, we get:
Ea / Eb = (12 * 1) / (6 * 3) = 2/1
Therefore, the ratio of induced e.m.f. in generator A and B is 3:1.
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Community Answer
Two generators A and B have 6 -poles each. Generator A has wave wound ...
B.3:1
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Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer?
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Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer?.
Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two generators A and B have 6 -poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. in generator A and B will be .....a)2 : 3b)3 : 1c)3 : 2d)1:3Correct answer is option 'B'. Can you explain this answer?.
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