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What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?
- a)0.25
- b)0.5
- c)0.75
- d)1
Correct answer is option 'A'. Can you explain this answer?
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What will be the flux density (in T) of material in free space if the...
Given that, magnetic field strength (H) = 2 × 105 A-m-1
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Magnetic flux density, B = μH = 4π × 10-7 × 2 × 105 = 0.25 T
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What will be the flux density (in T) of material in free space if the...
Given information:
Field strength of the material (H) = 2 × 10^5 A/m
Magnetic susceptibility of the material (χ) = 0.44 × 10^-3
To find:
Flux density (B) in Tesla (T)
Formula:
B = μ₀(H + M)
Where,
B is the flux density,
μ₀ is the permeability of free space,
H is the field strength, and
M is the magnetization of the material.
Calculation:
1. Permeability of free space:
The permeability of free space (μ₀) is a constant value and is equal to 4π × 10^-7 T·m/A.
2. Magnetization of the material:
Magnetization (M) is given by the formula:
M = χH
Where,
χ is the magnetic susceptibility of the material.
Substituting the given values:
M = (0.44 × 10^-3)(2 × 10^5)
M = 0.088 T
3. Flux density (B):
Using the formula mentioned earlier:
B = μ₀(H + M)
B = (4π × 10^-7 T·m/A)((2 × 10^5 A/m) + (0.088 T))
Calculating the value inside the parentheses:
(2 × 10^5 A/m) + (0.088 T) = 2.088 × 10^5 A/m
Substituting this value into the equation:
B = (4π × 10^-7 T·m/A)(2.088 × 10^5 A/m)
B = 8.35 × 10^-2 T
B ≈ 0.084 T
Therefore, the flux density of the material in free space is approximately 0.084 T.
Comparing the calculated value with the given options, we can see that the closest option is 0.25 T (option A).
Field strength of the material (H) = 2 × 10^5 A/m
Magnetic susceptibility of the material (χ) = 0.44 × 10^-3
To find:
Flux density (B) in Tesla (T)
Formula:
B = μ₀(H + M)
Where,
B is the flux density,
μ₀ is the permeability of free space,
H is the field strength, and
M is the magnetization of the material.
Calculation:
1. Permeability of free space:
The permeability of free space (μ₀) is a constant value and is equal to 4π × 10^-7 T·m/A.
2. Magnetization of the material:
Magnetization (M) is given by the formula:
M = χH
Where,
χ is the magnetic susceptibility of the material.
Substituting the given values:
M = (0.44 × 10^-3)(2 × 10^5)
M = 0.088 T
3. Flux density (B):
Using the formula mentioned earlier:
B = μ₀(H + M)
B = (4π × 10^-7 T·m/A)((2 × 10^5 A/m) + (0.088 T))
Calculating the value inside the parentheses:
(2 × 10^5 A/m) + (0.088 T) = 2.088 × 10^5 A/m
Substituting this value into the equation:
B = (4π × 10^-7 T·m/A)(2.088 × 10^5 A/m)
B = 8.35 × 10^-2 T
B ≈ 0.084 T
Therefore, the flux density of the material in free space is approximately 0.084 T.
Comparing the calculated value with the given options, we can see that the closest option is 0.25 T (option A).
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What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer?
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What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer?.
What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the flux density (in T) of material in free space if the field strength of the material is 2 × 105 A-m-1 and the magnetic susceptibility of the material is 0.44 × 10-3?a)0.25b)0.5c)0.75d)1Correct answer is option 'A'. Can you explain this answer?.
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