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The absolute minimum radius for a horizontal curve designed for speed of 100 kmph given the permissible values of superelevation 0.08 and coefficient of friction 0.12 will be
  • a)
    394 m
  • b)
    295 m
  • c)
    364 m
  • d)
    225 m
Correct answer is option 'A'. Can you explain this answer?
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Calculating the Absolute Minimum Radius for a Horizontal Curve

Given:
- Speed: 100 kmph
- Superelevation: 0.08
- Coefficient of friction: 0.12

Formula:
- Absolute minimum radius = (V^2/g)*(1/e+f)

Where,
- V = Speed in meters per second (100 kmph = 27.77 m/s)
- g = Acceleration due to gravity (9.81 m/s^2)
- e = Superelevation (0.08)
- f = Coefficient of friction (0.12)

Calculation:
- V = 27.77 m/s
- g = 9.81 m/s^2
- e = 0.08
- f = 0.12

Absolute minimum radius = (V^2/g)*(1/e+f)
= (27.77^2/9.81)*(1/0.08+0.12)
= 394.23 meters

Therefore, the absolute minimum radius for a horizontal curve designed for a speed of 100 kmph given the permissible values of superelevation 0.08 and coefficient of friction 0.12 will be 394 m.
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The absolute minimum radius for a horizontal curve designed for speed of 100 kmph given the permissible values of superelevation 0.08 and coefficient of friction 0.12 will bea)394 mb)295 mc)364 md)225 mCorrect answer is option 'A'. Can you explain this answer?
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